如何在下面的代码中将charx
数组转换为整数89?谢谢
int main(int argc,char *argv[]){
char y[13] = "0123456789012";
char x[3];
int integer_value;
x[0] = y[8];
x[1] = y[9];
x[3] = '\0';
integer_value=atoi(x);
}
如何在下面的代码中将charx
数组转换为整数89?谢谢
int main(int argc,char *argv[]){
char y[13] = "0123456789012";
char x[3];
int integer_value;
x[0] = y[8];
x[1] = y[9];
x[3] = '\0';
integer_value=atoi(x);
}