您可以在单个查询中执行此操作。我敢肯定这有很多变化,但这是我会使用的......
DECLARE
@node_id INT,
@new_parent_id INT
SELECT
@node_id = 5,
@new_parent = 1
UPDATE
yourTable
SET
parent_id = CASE WHEN yourTable.id = target_node.id THEN new_antiscendant.id
WHEN yourTable.id = descendant.id THEN target_node.parent_id
WHEN yourTable.id = new_descendant.id THEN target_node.id
END
FROM
yourTable AS target_node
LEFT JOIN
yourTable AS descendant
ON descendant.parent_id = target_node.id
LEFT JOIN
yourTable AS new_antiscendant
ON new_antiscendant.id = @new_parent_id
LEFT JOIN
yourTable AS new_descendant
ON COALESCE(new_descendant.parent_id, -1) = COALESCE(new_antiscendant.id, -1)
INNER JOIN
yourTable
ON yourTable.id IN (target_node.id, descendant.id, new_descendant.id)
WHERE
target_node.id = @node_id
即使 @new_parent_id 为 NULL 或列表中的最后一条记录,这也将起作用。
MySQL 不喜欢更新中的自联接,因此该方法可能是将 LEFT JOIN 放入临时表中以获取新映射。然后加入该表以在单个查询中更新所有三个记录。
INSERT INTO
yourTempTable
SELECT
yourTable.id AS node_id,
CASE WHEN yourTable.id = target_node.id THEN new_antiscendant.id
WHEN yourTable.id = descendant.id THEN target_node.parent_id
WHEN yourTable.id = new_descendant.id THEN target_node.id
END AS new_parent_id
FROM
yourTable AS target_node
LEFT JOIN
yourTable AS descendant
ON descendant.parent_id = target_node.id
LEFT JOIN
yourTable AS new_antiscendant
ON new_antiscendant.id = @new_parent_id
LEFT JOIN
yourTable AS new_descendant
ON COALESCE(new_descendant.parent_id, -1) = COALESCE(new_antiscendant.id, -1)
INNER JOIN
yourTable
ON yourTable.id IN (target_node.id, descendant.id, new_descendant.id)
WHERE
target_node.id = @node_id
UPDATE
yourTable
SET
parent_id = yourTempTable.newParentID
FROM
yourTable
INNER JOIN
yourTempTable
ON yourTempTamp.node_id = yourTable.id
(确切的语法取决于您的 RDBMS。)