0

我有这个需要插入数据库的数组。我下面的代码不起作用,我最终得到相同的值。

array(10) { [0]=>  array(1) { ["GymnastName"] => string(7) "ertwert"  }
            [1]=>  array(1) { ["GymnastName"] => string(6) "wergfb"  }
            [2]=>  array(1) { ["GymnastAge"] => string(8) "ewrtwert" }
            [3]=>  array(1) { ["GymnastAge"] => string(8) "dsfvsdtg" }
            [4]=>  array(1) { ["ParentsName"] => string(9) "werfgdsfv" }
            [5]=>  array(1) { ["ParentsName"] => string(9) "wetrgwerg" }
            [6]=>  array(1) { ["ParentsEmail"] => string(7) "erteqrt" }
            [7]=>  array(1) { ["ParentsEmail"] => string(6) "adfwer" }
            [8]=>  array(1) { ["ParentsPhone"] => string(7) "ertwert" }
            [9]=>  array(1) { ["ParentsPhone"]=> string(4) "qert" }
}

这是我的循环:

for ($i=0; $i<$l; $i++) {

    $name = $gymarray[$i];
    $age = $gymarray[$i];
    $parentname = $gymarray[$i];
    $parentemail = $gymarray[$i];
    $parentphone = $gymarray[$i];

    $db->insert statement here

本质上,我需要将记录插入为 GymnastName、GymnastAge、ParentsName、ParentsEmail、ParentsPhone。

我最终得到的最终代码是:

array(1) {
["GymnastName"]=>
string(7) "ertwert"
}

array(1) {
["GymnastName"]=>
string(7) "ertwert"
}

array(1) {
["GymnastName"]=>
string(7) "ertwert"
}

array(1) {
["GymnastName"]=>
string(7) "ertwert"
} 

array(1) {
["GymnastName"]=>
string(7) "ertwert"
}
4

1 回答 1

2

我猜你想做类似的事情

for ($i=0; $i<$l; $i) {

    $name        = $gymarray[$i]["GymnastName"];
    $age         = $gymarray[$i + 2]["GymnastAge"];
    $parentname  = $gymarray[$i + 4]["GymnastAge"];
    $parentemail = $gymarray[$i + 6]["ParentsEmail"];
    $parentphone = $gymarray[$i + 8]["ParentsPhone"];

    $db->insert statement here
}
于 2012-06-18T16:55:33.590 回答