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我正在尝试将带有一些 2D 数组成员变量的 C++ 类传递给 Python 脚本。二维数组直接分配到类中，独立于构造函数。我正在使用 boost_python 库进行此转换，而包装函数使用 add_property/reference_existing_object 函数，期望它从 C++ 脚本的双指针创建一个新的 Python 2D 数组。

但是，我收到一条错误消息，告诉我在处理数组时 boost 无法从 const double 转换为 double 。但是数组不应该首先设置为 const 吗？有可能我在这里。我是新手，自从我写 C++ 以来已经有一段时间了，所以我希望你们中的一些人能以一种简单的方式帮助解释这一点:) 如果我的方法不是要走的路，我怎么能传递这些数组？

我在这里发布类和包装函数以供参考。 

class Interface 
{
public:

   double zUpPatch1[NVALUES_UPSWEEP][N_VALUES_IN_TUPLE+1];
   double zUpPatch2[NVALUES_UPSWEEP][N_VALUES_IN_TUPLE+1];
   double zDownPatch1[NVALUES_UPSWEEP][N_VALUES_IN_TUPLE+1];
   double zDownPatch2[NVALUES_UPSWEEP][N_VALUES_IN_TUPLE+1];

   bool bNewData[N_VALUES_IN_TUPLE+1];
   int mrows, ncols;

   Interface();
   void GetRawData(int);
};

Interface::Interface()
{
   mrows = NVALUES_UPSWEEP;
   ncols = N_VALUES_IN_TUPLE+1;
}

BOOST_PYTHON_MODULE(GetRawDataPy_ext)
{
   using namespace boost::python;

   class_<Interface>("Interface", init<>())
     .def("GetRawData", &Interface::GetRawData)
     .def_readwrite("mrows", &Interface::mrows)
     .def_readwrite("ncols", &Interface::ncols)
     .def_readwrite("bNewData", &Interface::bNewData)

     .add_property("zUpPatch1",
     make_getter(&Interface::zUpPatch1, return_value_policy<reference_existing_object>()),
     make_setter(&Interface::zUpPatch1, return_value_policy<reference_existing_object>()))

     .add_property("zUpPatch2",
     make_getter(&Interface::zUpPatch2, return_value_policy<reference_existing_object>()),
     make_setter(&Interface::zUpPatch2, return_value_policy<reference_existing_object>()))

     .add_property("zDownPatch1",
     make_getter(&Interface::zDownPatch2, return_value_policy<reference_existing_object>()),
     make_setter(&Interface::zDownPatch2, return_value_policy<reference_existing_object>()))

     .add_property("zDownPatch2",
     make_getter(&Interface::zDownPatch2, return_value_policy<reference_existing_object>()),
     make_setter(&Interface::zDownPatch2, return_value_policy<reference_existing_object>()))

     .add_property("bNewData",
     make_getter(&Interface::bNewData, return_value_policy<reference_existing_object>()),
     make_setter(&Interface::bNewData, return_value_policy<reference_existing_object>()))
  ;
}

这是来自 boost 编译器的错误消息的摘录：

C:\...\.../data_members.hpp(64) : error C2440: '=' : cannot convert from 
'const double [1000][5]' to double [1000][5]'
          There is no context in wich this conversion is possible
C:\...\.../data_members.hpp(63) : while compiling class template member function 
'void boost::python::detail::member<Data,Class>::operator ()(Class &,const double (&))   const'
    with
    [
        Data=double [1000][5],
        Class=Class
    ]

提前致谢！

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