linux - 如何使用 Shell 脚本解析报告？

Question

我有一个命令行程序，可以打印出报告，例如：

I found 0 problems on your database,
0 problems were found on your database

等等。

我想编写一个仅将数字导出到变量的 linux shell 脚本。我找不到这样做的正确方法。我怀疑我没有grep正确使用（或者有更好的命令）；IE

I found 43 problems on your database,
43 problems were found on your database
$VAR=43

请指教

Answer 1

$ var=$(echo -e "I found 43 problems on your database,
43 problems were found on your database" | grep -om 1 '[0-9]\+')
$ echo $var
43

Answer 2

我发现 Lev Levitsky 的解决方案非常完美，但我只想补充一点，如果您的报告包含许多带有数字的此类行并且您想要处理每一行，您将使用如下内容：

cat report | grep -o '[0-9]\+' | while read var
do
  # do something with var
done