问题:
在不使用任何 CSS3 选择器的情况下设置 SQL 查询中最后一行的样式。
PHP代码:
while ($item = mysql_fetch_assoc($itemsresult))
{
$answer = "SELECT IID, Comment FROM betyg_answers WHERE EID = '{$EID}' AND CID = '{$item['CID']}' ORDER BY ID ASC";
$answerresult = mysql_query($answer) or die ('Error (' . mysql_errno() . ') ' . mysql_error());
$answer = mysql_fetch_assoc($answerresult);
if ($answer['IID'] == $item['IID'])
{
$html .= '
<tr>
<td class="arrow" style="'.$arrow.'"><img src="./img/circle_arrow_right.png" class="arrowimage"></td>
<td class="numbers" style="'.$numbers.'">'.$itemcounter.'.</td>
<td class="text" style="'.$text.'">'.$item['Description'].'</td>
</tr>
';
}
else
{
$html .= '
<tr>
<td class="arrow" style="'.$arrow.'"> </td>
<td class="numbers" style="'.$numbers.'">'.$itemcounter.'.</td>
<td class="text" style="'.$text.'">'.$item['Description'].'</td>
</tr>
';
}
$itemcounter++;
}
SQL 查询中的最后一行应该打印:
$html .= '
<tr>
<td class="arrow" style="'.$lastarrow.'"> </td>
<td class="numbers" style="'.$lastnumbers.'">'.$itemcounter.'.</td>
<td class="text" style="'.$lasttext.'">'.$item['Description'].'</td>
</tr>
';
问题:
需要在 while 循环中添加什么以便它识别最后一行并打印不同的代码?