mysql - mysql：为单个列计数特定值出现的行数

Question

我正在使用 MySQL 查询编写报告。它有多个我报告的列。其中，有一列包含许多不同的值（行前只有一个值）。我需要计算该列中的两个特定值。然后按类型对最终结果进行分组：

桌子

ID Name  has passed  Type  
 1  abc      yes (1)   z  
 2  xyz      yes (1)   x  
 3  cde      no  (0)   y  
 4  abc      yes (1)   z  
 5  cde      no  (0)   z  
 6  xyz      no  (0)   y  

我的预期结果是：

For Type x  
 total records = 1  
 yes count = 1     
 total abc = 0  
 total cde = 0  

For Type y  
 total records = 2  
 yes count = 0     
 total abc = 0  
 total cde = 1  

For Type z  
 total records = 3  
 yes count = 2   
 total abc = 2  
 total cde = 1  

请注意，我们不计算名称 xyz 或任何其他名称。

Answer 1

SELECT
    type,
    COUNT(*) AS total_records,
    COUNT(IF(has_passed, 1, NULL)) AS yes_count,
    COUNT(IF(name = 'abc', 1, NULL)) AS total_abc,
    COUNT(IF(name = 'cde', 1, NULL)) AS total_cde
FROM
    table
GROUP BY
    type

Answer 2

在我的脑海中（现在无法访问数据库进行测试，抱歉）......也许这样的事情会起作用（假设你存储 0 和 1 来表示“通过”）？

SELECT
   type,
   SUM(passed) as "Yes count",
   SUM(case when name = 'abc' then 1 else 0 end) as "Total abc",
   SUM(case when name = 'cde' then 1 else 0 end) as "Total cde",
   COUNT(1) as "Total records"
FROM
   myTable
GROUP BY
   type
;