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我正在使用 android 2.1 平台。我拥有的代码将显示模拟器联系人列表中所有人的姓名号码和电子邮件 ID，通过使用此代码，我将获得上述要求。我的模拟器中有一些联系人，我又创建了两个联系人（比如 C 和 D）。但问题是

问题 1.如果我创建一个姓名和号码不是电子邮件的新联系人，该联系人将从联系人那里获取 电子邮件 ID。例如：如果我创建一个名称 C 没有电子邮件 ID 但 D 有电子邮件 ID，则 D 是模拟器中已经存在的联系人。 C 将获取 D 的电子邮件ID。C 和 D 具有相同的电子邮件 ID。

问题 2。如果我再次创建一个名称为 email 但没有 number的新联系人，此联系人将从我之前创建的联系人中获取 号码。例如：如果我创建名称 E 没有号码，但它将采用联系人 C 的号码。因此C 和 E 具有相同的号码。

我正在使用此代码

public class GetAllDatas extends Activity {

ListView lvItem;
private Button btnAdd;
String displayName="", emailAddress="", phoneNumber="";
ArrayList<String> contactlist=new ArrayList<String>(); 
ArrayAdapter<String> itemAdapter;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    lvItem = (ListView)this.findViewById(R.id.lvitems); 
    btnAdd = (Button)this.findViewById(R.id.btnAddItem);

    itemAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1,contactlist);
    lvItem.setAdapter(itemAdapter);

    btnAdd.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            readContacts();
        }
    });

} 

private void readContacts()
{
    ContentResolver cr =getContentResolver();
    Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
    while (cursor.moveToNext()) 
    {
        displayName = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));       
        String id = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));


        Cursor emails = cr.query(Email.CONTENT_URI,null,Email.CONTACT_ID + " = " + id, null, null);
        while (emails.moveToNext()) 
        { 
            emailAddress = emails.getString(emails.getColumnIndex(Email.DATA));
            break;
        }
        emails.close();


        if(Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0)
        {
            Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?",new String[]{id}, null);
            while (pCur.moveToNext()) 
            {
                 phoneNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                break;  
            } 
            pCur.close();
        }


        //  To display the Details
        contactlist.add(displayName+", "+phoneNumber+", "+ emailAddress+"\n");
        itemAdapter.notifyDataSetChanged();
    }
    Collections.sort(contactlist);
    cursor.close(); 
}
}

我怎么解决这个问题 ？

4

2 回答 2

2

正如我理解你的问题..

在引用变量中添加新项目之前，只需擦除前一个.. 就像， 

emailAddress = "" ; 
displayName  = "" ;
phoneNumber  = "" ;

在您的 while 循环中获取联系信息并将其添加到列表中..

private void readContacts()
{
    ContentResolver cr =getContentResolver();
    Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
    while (cursor.moveToNext()) 
    {
        emailAddress = "" ;
        displayName  = "" ;
        phoneNumber  = "" ;

        displayName = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));       
        String id = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));

        Cursor emails = cr.query(Email.CONTENT_URI,null,Email.CONTACT_ID + " = " + id, null, null);
        while (emails.moveToNext()) 
        { 
            emailAddress = emails.getString(emails.getColumnIndex(Email.DATA));
            break;
        }
        emails.close(); 
        if(Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0)
        {
            Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?",new String[]{id}, null);
            while (pCur.moveToNext()) 
            {
                 phoneNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                break;  
            } 
            pCur.close();
        }   

        //  To display the Details
        contactlist.add(displayName+", "+phoneNumber+", "+ emailAddress+"\n");          
    }
    Collections.sort(contactlist);
    itemAdapter.notifyDataSetChanged();
    cursor.close(); 
}
于 2012-06-15T09:54:28.373 回答
0

试试这个…………

         public void readContacts(){
    ContentResolver cr = getContentResolver();
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
           null, null, null, null);

    contactName=new String[cur.getCount()];
   contactNumber=new String[cur.getCount()][];
   contactEmail=new String[cur.getCount()][];
   int i=0;
    if (cur.getCount() > 0) {
       while (cur.moveToNext()) {
           String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
           String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
           contactName[i]=name;
           Log.e("Contact Name",contactName[i]);
           if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {


               // get the phone number
               Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
                                      ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?",
                                      new String[]{id}, null);
               contactNumber[i]=new String[pCur.getCount()];
               int j=0;
               while (pCur.moveToNext()) {
                     String phone = pCur.getString(
                            pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

                contactNumber[i][j]=phone;
                Log.d("Contact number",contactNumber[i][j]);
                j++;
               }
               pCur.close();
           }
               // get email and type

              Cursor emailCur = cr.query(
                       ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                       null,
                       ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
                       new String[]{id}, null);
              contactEmail[i]=new String[emailCur.getCount()];
              int k=0;
               while (emailCur.moveToNext()) {

                   String email = emailCur.getString(
                                 emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
                   String emailType = emailCur.getString(
                                 emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));

                contactEmail[i][k]=email;
                Log.v("Contact email",contactEmail[i][k]);
                k++;
               }
               emailCur.close();


           }
       } i++;
  }
于 2012-06-15T10:07:54.600 回答