0

tbl_group

( group_id, user_id, group_name, group_image, group_description, doi)

(9, 28, 'bbb', '1339660354imagesv.jpg', 'dfdsfsdf', '2012-06-14 13:22:34'),
(11, 1, 'cccc', '', '', '2012-06-14 14:49:56'),
(22, 1, '000', '', '', '2012-06-14 15:31:43');

tbl_groupnews

news_id, user_id, group_id, group_news,doi

(1, 1, 22, 'hi \n', '2012-06-14 16:20:36'),
(2, 1, 22, 'hello', '2012-06-14 16:21:59'),
(3, 1, 22, '1111', '2012-06-14 16:25:13'),
(4, 1, 22, 'jj', '2012-06-14 16:34:41'),
(5, 28, 9, 'hi', '2012-06-15 09:48:47');

tbl_groupmembers

groupmember_id, group_id, adder, member,doi

(1, 9, 28, 1, '2012-06-14 13:22:35'),
(2, 9, 28, 66, '2012-06-14 13:22:35'),
(4, 11, 1, 2, '2012-06-14 14:49:56'),
(5, 11, 1, 28, '2012-06-14 14:49:56'),
(6, 11, 1, 62, '2012-06-14 14:49:56'),
(36, 22, 1, 28, '2012-06-14 16:15:41'),
(37, 22, 1, 62, '2012-06-14 16:16:55'),
(38, 22, 1, 66, '2012-06-14 16:18:35'),
(39, 22, 1, 70, '2012-06-14 16:19:33');

我运行查询

  SELECT tbl_groups.*,
         COUNT (tbl_groupnews.news_id) AS cn1,
         COUNT (tbl_groupmembers.group_id) AS cn2
    FROM tbl_groups
    LEFT JOIN tbl_groupnews ON tbl_groups.group_id = tbl_groupnews.group_id
    LEFT JOIN tbl_groupmembers ON tbl_groupmembers.group_id = tbl_groups.group_id
   WHERE (tbl_groups.user_id = 28 OR tbl_groupmembers.member = 28)
GROUP BY tbl_groups.group_id

我的要求是我需要从 group、count of news 和 count of members 中获取所有值WHERE user_id = 28 or member id = 28。

谁能帮我找到解决方案？

4

2 回答 2

1

试试这样：

SELECT tbl_groups.*,          
COUNT (tbl_groupnews.news_id) AS cn1,          
COUNT (tbl_groupmembers.group_id) AS cn2     
FROM tbl_groups     
LEFT JOIN tbl_groupnews ON tbl_groups.group_id = tbl_groupnews.group_id 
AND tbl_groups.user_id = 28    
LEFT JOIN tbl_groupmembers ON tbl_groupmembers.group_id = tbl_groups.group_id  
AND tbl_groupmembers.MEMBER = 28  
GROUP BY tbl_groups.group_id
于 2012-06-15T06:59:59.113 回答
0

如果您从 tbl_groups 中选择所有列，它们需要在您的 group by 语句中

SELECT tbl_groups.*,COUNT(distinct tbl_groupnews.news_id) as cn1,
        COUNT(distinct tbl_groupmembers.group_id) as cn2
    FROM tbl_groups
    LEFT JOIN tbl_groupnews ON tbl_groups.group_id=tbl_groupnews.group_id
    LEFT JOIN tbl_groupmembers ON tbl_groupmembers.group_id=tbl_groups.group_id
    WHERE (tbl_groups.user_id  = 28 or tbl_groupmembers.member=28)
    GROUP BY tbl_groups.group_id,tbl_groups.user_id, tbl_groups.group_name, tbl_groups.group_image, tbl_groups.group_description, tbl_groups.doi
于 2012-06-15T07:07:51.780 回答