146

我需要解析一个字符串并在每个 Guid 值周围添加单引号。我在想我可以使用正则表达式来做到这一点，但我不完全是正则表达式大师。

是否有一个好的正则表达式可用于识别 Guid？

我的第二个问题是一旦我找到了一个有效的正则表达式，我假设我会使用Regex.Replace(String, String, MatchEvaluator)，但我不太确定语法。也许是这样的：

return Regex.Replace(stringToFindMatch, GuidRegex, match =>
{
    return string.Format("'{0}'", match.Groups[0].ToString());
});

我试图解析的字符串可能如下所示：

“选择密码co0_.PASSWORD_CONFIG_ID 作为PASSWORD1_46_0_，从PASSWORD_CONFIG 密码co0_ WHERE passwordco0_.PASSWORD_CONFIG_ID=baf04077-a3c0-454b-ac6f-9fec00b8e170；@p0 = baf04077-a3c0-454b-ac6f-9fec00b8e170；@p0 = baf04077-a3c0-454b-ac6f-9fec00b8e10)]"

4

6 回答 6

218

这个很简单，不需要你说的委托。

resultString = Regex.Replace(subjectString, 
     @"(?im)^[{(]?[0-9A-F]{8}[-]?(?:[0-9A-F]{4}[-]?){3}[0-9A-F]{12}[)}]?$", 
     "'$0'");

这与以下样式匹配，这些样式都是 GUID 的等效且可接受的格式。

ca761232ed4211cebacd00aa0057b223
CA761232-ED42-11CE-BACD-00AA0057B223
{CA761232-ED42-11CE-BACD-00AA0057B223}
(CA761232-ED42-11CE-BACD-00AA0057B223)

更新 1

@NonStatic 在评论中指出，上述正则表达式将匹配具有错误结束分隔符的误报。

这可以通过广泛支持的正则表达式条件来避免。

Conditionals are supported by the JGsoft engine, Perl, PCRE, Python, and the .NET framework. Ruby supports them starting with version 2.0. Languages such as Delphi, PHP, and R that have regex features based on PCRE also support conditionals. (source http://www.regular-expressions.info/conditional.html)

The regex that follows Will match

{123}
(123)
123

And will not match

{123)
(123}
{123
(123
123}
123)

Regex:

^({)?(\()?\d+(?(1)})(?(2)\))$

The solutions is simplified to match only numbers to show in a more clear way what is required if needed.

于 2012-06-14T20:37:36.033 回答
59

Most basic regex is following:

(^([0-9A-Fa-f]{8}[-][0-9A-Fa-f]{4}[-][0-9A-Fa-f]{4}[-][0-9A-Fa-f]{4}[-][0-9A-Fa-f]{12})$)

or you could paste it here.

Hope this saves you some time.

于 2016-02-26T09:42:43.850 回答
29

For C# .Net to find and replace any guid looking string from the given text,

Use this RegEx:

[({]?[a-fA-F0-9]{8}[-]?([a-fA-F0-9]{4}[-]?){3}[a-fA-F0-9]{12}[})]?

Example C# code:

var result = Regex.Replace(
      source, 
      @"[({]?[a-fA-F0-9]{8}[-]?([a-fA-F0-9]{4}[-]?){3}[a-fA-F0-9]{12}[})]?", 
      @"${ __UUID}", 
      RegexOptions.IgnoreCase
);

Surely works! And it matches & replaces the following styles, which are all equivalent and acceptable formats for a GUID.

"aa761232bd4211cfaacd00aa0057b243" 
"AA761232-BD42-11CF-AACD-00AA0057B243" 
"{AA761232-BD42-11CF-AACD-00AA0057B243}" 
"(AA761232-BD42-11CF-AACD-00AA0057B243)"
于 2018-04-12T02:23:05.783 回答
8

In .NET Framework 4 there is enhancement System.Guid structure, These includes new TryParse and TryParseExact methods to Parse GUID. Here is example for this.

    //Generate New GUID
    Guid objGuid = Guid.NewGuid();
    //Take invalid guid format
    string strGUID = "aaa-a-a-a-a";

    Guid newGuid;

    if (Guid.TryParse(objGuid.ToString(), out newGuid) == true)
    {
        Response.Write(string.Format("<br/>{0} is Valid GUID.", objGuid.ToString()));
    }
    else
    {
        Response.Write(string.Format("<br/>{0} is InValid GUID.", objGuid.ToString()));
    }


    Guid newTmpGuid;

    if (Guid.TryParse(strGUID, out newTmpGuid) == true)
    {
        Response.Write(string.Format("<br/>{0} is Valid GUID.", strGUID));
    }
    else
    {
        Response.Write(string.Format("<br/>{0} is InValid GUID.", strGUID));
    }

In this example we create new guid object and also take one string variable which has invalid guid. After that we use TryParse method to validate that both variable has valid guid format or not. By running example you can see that string variable has not valid guid format and it gives message of "InValid guid". If string variable has valid guid than this will return true in TryParse method.

于 2012-06-28T10:25:00.210 回答
8

You can easily auto-generate the C# code using: http://regexhero.net/tester/.

Its free.

Here is how I did it:

enter image description here

The website then auto-generates the .NET code:

string strRegex = @"\b[A-F0-9]{8}(?:-[A-F0-9]{4}){3}-[A-F0-9]{12}\b";
Regex myRegex = new Regex(strRegex, RegexOptions.None);
string strTargetString = @"     {CD73FAD2-E226-4715-B6FA-14EDF0764162}.Debug|x64.ActiveCfg =         Debug|x64";
string strReplace = @"""$0""";

return myRegex.Replace(strTargetString, strReplace);
于 2014-03-27T16:12:28.490 回答
7

I use an easier regex pattern

^[0-9A-Fa-f\-]{36}$
于 2019-06-05T14:02:13.047 回答