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我有以下课程：

class A {
    String s;
}

以及以下class A对象列表列表：

[{1s, 3f, 46h}, {333s, 67b, 1d, 67m, 67h}, {3a, 3x}, {34n, 22o, 34s},
 {40f, 22x, 4m}... and so on]

我只需要遍历这个列表，获取结果并推送到另一个输出数组列表中。现在将包含在结果数组列表中的内容：

1. Just skip those elements from the above input arrayList
   which have more than one String with same prefix(only the last character
   is the suffix here which will always be a single character alphabet; not digit).
   For example: from the above input arrayList the first element({1s, 3f, 46h}) 
   won't be skipped and will be pushed into the output arrayList
   as it doesn't have any String with the same prefix; as 1, 3 and 46 are different.
   But 2nd, 3rd and 4th elements will be skipped as they have matches
   (three prefixes with same 67 in 2nd element, two prefixes with same 3 in 3rd element
   and two prefixes with same 34 in 4th element).

   So, for the above input arrayList the output arrayList will be:
   [{1s, 3f, 46h}, {40f, 22x, 4m}]

任何人都可以建议我如何以简单有效的方式完成上述工作。如果可能，请提供一些示例代码。

谢谢！

4

2 回答 2

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因此，如果我为此编写测试，我会看到我需要的一件事是能够确定前缀。给定一个带有字符串“55p”的A，前缀应该是“55”。为此写一个测试。前缀方法属于哪里？可能在A类本身。它应该看起来像：

public String prefix() {
    return ...;
}

一旦你有了那个方法，就很容易遍历列表中的所有 A 并确定它们中的任何一个是否具有相同的前缀。

于 2012-06-14T18:29:28.807 回答
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考虑以下：

我已经尝试了一个逻辑，如果这对你有用，我会很高兴。

`ArrayList<A> arrList` = [{1s, 3f, 46h}, {333s, 67b,67m, 67h}, {3a, 3x}, {40f, 22x, 4m}... and so on]


 ArrayList<String> newList = new ArrayList<String>();

for ( A a: arrList){

        for(String s : a) {

             int[] temp = a.indexOf(s);

             if (temp > 1){

                break; // will break the immediate loop, NOT the Outer loop

             }

            else{
                     newList.add(s);

              }

      }


}
于 2012-06-14T18:02:00.367 回答