我正在尝试在同一模型中调用模型方法,但它没有按预期工作。这是我的课,有两种不起作用的方法
class mymodel extends CI_Model{
public function __construct(){
parent::__construct();
$this->tablea = 'tablea';
$this->tableb = 'tableb';
}
public function saveData($data){
$dataCopy['revisionkey'] = $this->getRevisionKey($data['id']);
//check and condition revision key to be int with +1 from last one
$this->db->insert($this->tableb, $dataCopy);
$this->db->where('id', $id);
return $this->db->update($this->user_table, $data) ? true : false;
}
public function getRevisionKey($id){
$this->db->select($this->revision_tablea.'.revisions_number as revisions_number')
->from($this->revision_tablea)
->where($this->revision_tablea.'.id', $id)
->order_by($this->revision_table.'.revisions_number', 'asc')
->limit(1);
$query = $this->db->get();
if ($query->num_rows() > 0){
return $query->row_array();
}else{
return 0;
}
}
}
现在方法getRevisionKey()
应该产生如下查询
SELECT `tableb`.`revisions_number` as revisions_number FROM (`tableb`) WHERE `tableb`.`id` = '26' ORDER BY `tableb`.`revisions_number` asc LIMIT 1
但它会产生如下查询
SELECT `tableb`.`revisions_number` as revisions_number FROM (`tableb`) WHERE `id` = '26' AND `tableb`.`id` = '26' ORDER BY `tableb`.`revisions_number` asc LIMIT 1
这当然是由于在模型中调用了相同的方法,如果在模型之外使用此方法可以正常工作。这个问题有什么解决办法吗?
编辑
重写此getRevisionKey()
修复程序。这是新版本
public function getRevisionKey($id){
$sqlQuery = $this->db->select($this->revision_tablea.'.revisions_number as revisions_number')
->from($this->revision_tablea)
->order_by($this->revision_table.'.revisions_number', 'asc')
->limit(1);
$query = $sqlQuery->where($this->revision_tablea.'.id', $id)->get();
if ($query->num_rows() > 0){
return $query->row_array();
}else{
return 0;
}
}