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我刚刚发现了如何基于另一个数组循环一个数组，但我的问题是，如果第二个数组只是 1 个对象，那么它可以正常工作，但我想让它与两个对象一起工作。

这是一个例子，它是如何工作的，

$shorten = array(
  0 => 'ECAR',
  1 => 'CCAR',
  2 => 'ICAR',
  3 => 'SCAR',
  4 => 'FCAR',
  5 => 'PCAR',
);

$data = array(
  'Hertz' => array(
        'ECAR' => '49.21',
        'CCAR' => '71.04',
        'ICAR' => '89.58',
        'SCAR' => '100.00',
    )
  ),
  'Avis' => array(
        'ECAR' => '412.00',
        'CCAR' => '347.00',
        'ICAR' => '285.00',
        'SCAR' => '224.00',
        'FCAR' => '165.00',
        'PCAR' => '100.00',
    )
  ),
);

// default array as the base
$shorten = array_combine($shorten, array_fill(0, count($shorten), 'n/a'));

foreach($data as &$array) {
    // merge to get set members
    $array = array_merge($shorten, $array);
}
unset($array);

print_r($data);

但我想让它和这个一起工作，

$shorten = array(
  0 => 'ECAR',
  1 => 'CCAR',
  2 => 'ICAR',
  3 => 'SCAR',
  4 => 'FCAR',
  5 => 'PCAR',
);

$data = array(
  'Hertz' => array(
    'NYCT01' => array(
        'ECAR' => '49.21',
        'CCAR' => '71.04',
        'ICAR' => '89.58',
        'SCAR' => '100.00',
    )
  ),
  'Avis' => array(
    'NYCT01' => array(
        'ECAR' => '412.00',
        'CCAR' => '347.00',
        'ICAR' => '285.00',
        'SCAR' => '224.00',
        'FCAR' => '165.00',
        'PCAR' => '100.00',
    )
  ),
);

// default array as the base
$shorten = array_combine($shorten, array_fill(0, count($shorten), 'n/a'));

foreach($data as $firstArray) {
    foreach($firstArray as &$array){
        // merge to get set members
        $array = array_merge($shorten, $array);
    }
}
unset($array);

print_r($data);

这就是我想要的，

Array
(
    [Hertz] => Array
        (
            [ECAR] => 49.21
            [CCAR] => 71.04
            [ICAR] => 89.58
            [SCAR] => 100.00
            [FCAR] => n/a
            [PCAR] => n/a
        )

    [Avis] => Array
        (
            [ECAR] => 412.00
            [CCAR] => 347.00
            [ICAR] => 285.00
            [SCAR] => 224.00
            [FCAR] => 165.00
            [PCAR] => 100.00
        )

)
4

2 回答 2

1 
foreach($data AS $company => $nyc){
    $inner = $nyc['NYCT01'];
    foreach($shorten AS $car){
        if(array_key_exists($car, $inner)){
            $output[$company][$car] = $inner[$car];
        }else {
            $output[$company][$car] = "n/a";
        }
    }
}

只需遍历数据并检查任何汽车的键是否存在于 NYCT01 数组中，如果它确实设置了值，否则为“n/a”。

我的输出：

Array
(
    [Hertz] => Array
        (
            [ECAR] => 49.21
            [CCAR] => 71.04
            [ICAR] => 89.58
            [SCAR] => 100.00
            [FCAR] => n/a
            [PCAR] => n/a
        )

    [Avis] => Array
        (
            [ECAR] => 412.00
            [CCAR] => 347.00
            [ICAR] => 285.00
            [SCAR] => 224.00
            [FCAR] => 165.00
            [PCAR] => 100.00
        )

)
于 2012-06-13T14:19:53.023 回答
0

好的，得到它的工作这是我想的真正的代码，

foreach($data as $company => $nyc){
    foreach($nyc as $inner => $s){
        foreach($shorten as $car){
            if(array_key_exists($car, $nyc[$inner])){
                $output[$company][$car] = $nyc[$inner][$car];
            }else {
                $output[$company][$car] = "n/a";
            }
        }
    }
}

非常感谢你的帮助马库斯，

祝你好运。

于 2012-06-13T15:12:46.467 回答