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我希望在使用ASP.NET Web API时从客户端应用程序对用户进行身份验证。我已经观看了网站上的所有视频，还阅读了这个论坛帖子。

正确放置[Authorize]属性会返回一个401 Unauthorized状态。但是，我需要知道如何允许用户登录 API。

我想从 Android 应用程序向 API 提供用户凭据，让用户登录，然后对所有后续 API 调用进行预身份验证。

4

3 回答 3

137

允许用户登录 API

您需要随请求一起发送有效的表单身份验证 cookie。此 cookie 通常由服务器在LogOn通过调用[FormsAuthentication.SetAuthCookie方法进行身份验证（操作）时发送（参见MSDN）。

所以客户端需要执行2个步骤：

  1. LogOn通过发送用户名和密码向操作发送 HTTP 请求。反过来，此操作将调用该FormsAuthentication.SetAuthCookie方法（如果凭据有效），该方法又将在响应中设置表单身份验证 cookie。
  2. [Authorize]通过发送在第一个请求中检索到的表单身份验证 cookie，将HTTP 请求发送到受保护的操作。

让我们举个例子。假设您在 Web 应用程序中定义了 2 个 API 控制器：

第一个负责处理身份验证：

public class AccountController : ApiController
{
    public bool Post(LogOnModel model)
    {
        if (model.Username == "john" && model.Password == "secret")
        {
            FormsAuthentication.SetAuthCookie(model.Username, false);
            return true;
        }

        return false;
    }
}

第二个包含只有授权用户才能看到的受保护操作：

[Authorize]
public class UsersController : ApiController
{
    public string Get()
    {
        return "This is a top secret material that only authorized users can see";
    }
}

现在我们可以编写一个使用这个 API 的客户端应用程序。这是一个简单的控制台应用程序示例（确保您已安装Microsoft.AspNet.WebApi.Client和Microsoft.Net.HttpNuGet 包）：

using System;
using System.Net.Http;
using System.Threading;

class Program
{
    static void Main()
    {
        using (var httpClient = new HttpClient())
        {
            var response = httpClient.PostAsJsonAsync(
                "http://localhost:26845/api/account", 
                new { username = "john", password = "secret" }, 
                CancellationToken.None
            ).Result;
            response.EnsureSuccessStatusCode();

            bool success = response.Content.ReadAsAsync<bool>().Result;
            if (success)
            {
                var secret = httpClient.GetStringAsync("http://localhost:26845/api/users");
                Console.WriteLine(secret.Result);
            }
            else
            {
                Console.WriteLine("Sorry you provided wrong credentials");
            }
        }
    }
}

以下是 2 个 HTTP 请求在网络上的样子：

认证请求：

POST /api/account HTTP/1.1
Content-Type: application/json; charset=utf-8
Host: localhost:26845
Content-Length: 39
Connection: Keep-Alive

{"username":"john","password":"secret"}

认证响应：

HTTP/1.1 200 OK
Server: ASP.NET Development Server/10.0.0.0
Date: Wed, 13 Jun 2012 13:24:41 GMT
X-AspNet-Version: 4.0.30319
Set-Cookie: .ASPXAUTH=REMOVED FOR BREVITY; path=/; HttpOnly
Cache-Control: no-cache
Pragma: no-cache
Expires: -1
Content-Type: application/json; charset=utf-8
Content-Length: 4
Connection: Close

true

请求受保护的数据：

GET /api/users HTTP/1.1
Host: localhost:26845
Cookie: .ASPXAUTH=REMOVED FOR BREVITY

对受保护数据的响应：

HTTP/1.1 200 OK
Server: ASP.NET Development Server/10.0.0.0
Date: Wed, 13 Jun 2012 13:24:41 GMT
X-AspNet-Version: 4.0.30319
Cache-Control: no-cache
Pragma: no-cache
Expires: -1
Content-Type: application/json; charset=utf-8
Content-Length: 66
Connection: Close

"This is a top secret material that only authorized users can see"
于 2012-06-13T12:41:58.380 回答
12

我以安卓为例。

public abstract class HttpHelper {

private final static String TAG = "HttpHelper";
private final static String API_URL = "http://your.url/api/";

private static CookieStore sCookieStore;

public static String invokePost(String action, List<NameValuePair> params) {
    try {
        String url = API_URL + action + "/";
        Log.d(TAG, "url is" + url);
        HttpPost httpPost = new HttpPost(url);
        if (params != null && params.size() > 0) {
            HttpEntity entity = new UrlEncodedFormEntity(params, "UTF-8");
            httpPost.setEntity(entity);
        }
        return invoke(httpPost);
    } catch (Exception e) {
        Log.e(TAG, e.toString());
    }

    return null;
}

public static String invokePost(String action) {
    return invokePost(action, null);
}

public static String invokeGet(String action, List<NameValuePair> params) {
    try {
        StringBuilder sb = new StringBuilder(API_URL);
        sb.append(action);
        if (params != null) {
            for (NameValuePair param : params) {
                sb.append("?");
                sb.append(param.getName());
                sb.append("=");
                sb.append(param.getValue());
            }
        }
        Log.d(TAG, "url is" + sb.toString());
        HttpGet httpGet = new HttpGet(sb.toString());
        return invoke(httpGet);
    } catch (Exception e) {
        Log.e(TAG, e.toString());
    }

    return null;
}

public static String invokeGet(String action) {
    return invokeGet(action, null);
}

private static String invoke(HttpUriRequest request)
        throws ClientProtocolException, IOException {
    String result = null;
    DefaultHttpClient httpClient = new DefaultHttpClient();

    // restore cookie
    if (sCookieStore != null) {
        httpClient.setCookieStore(sCookieStore);
    }

    HttpResponse response = httpClient.execute(request);

    StringBuilder builder = new StringBuilder();
    BufferedReader reader = new BufferedReader(new InputStreamReader(
            response.getEntity().getContent()));
    for (String s = reader.readLine(); s != null; s = reader.readLine()) {
        builder.append(s);
    }
    result = builder.toString();
    Log.d(TAG, "result is ( " + result + " )");

    // store cookie
    sCookieStore = ((AbstractHttpClient) httpClient).getCookieStore();
    return result;
}

请注意： i.localhost 不能使用。Android 设备将 localhost 视为自己的主机。ii.如果在 IIS 中部署 Web API，则必须打开 Form 身份验证。

于 2013-04-26T13:52:58.553 回答
0

使用此代码并访问数据库

[HttpPost]
[Route("login")]
public IHttpActionResult Login(LoginRequest request)
{
       CheckModelState();
       ApiResponse<LoginApiResponse> response = new ApiResponse<LoginApiResponse>();
       LoginResponse user;
       var count = 0;
       RoleName roleName = new RoleName();
       using (var authManager = InspectorBusinessFacade.GetAuthManagerInstance())
       {
           user = authManager.Authenticate(request); 
       } reponse(ok) 
}
于 2016-12-05T09:46:20.633 回答