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原谅我这个不漂亮的代码，但我试图让它首先工作。（“当然这只是暂时的。除非它有效”-red green）

我正在尝试创建一个函数，它将以我需要的样式格式化数字列。它看起来像这样。

    frmt <- function(x, rates=FALSE, thou=FALSE) {
  ifelse(x==0, "0", 
  ifelse(x < 0.01 & thou==TRUE, "<0.01", 
  ifelse(x < 0.1 & thou==FALSE, "<0.1", 
  ifelse(signif(x, 2) < 1 & thou==TRUE, formatC(round(x,3), format='f', digits=3),
  ifelse(signif(x, 2) < 1, formatC(round(x,2), format='f', digits=2), 
  ifelse(signif(x, 2) < 10, formatC(round(x,2), format='f', digits=1),
  ifelse(rates==FALSE, formatC(signif(x, 2), big.mark=" ", format='d'), 
  ifelse(signif(x, 3) < 100, formatC(signif(x, 2), big.mark=" ", format='d'), formatC(signif(x, 3), big.mark=" ", format='d')))))))))
}

它对此非常有用：

> frmt(1413.612)
[1] "1 400"

但不是这个：

> frmt(c(0.0001, 0.0213, 0.25413, 1.0123, 9.9123, 15.124, 112.05, 1413.612, NA))
[1] "<0.1" "<0.1" "0.25" "1.0"  "9.9"  "0"    "0"    "0"    NA
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1 回答 1

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这是我终于开始工作的代码

    frmt <- function(x, rates=FALSE, thou=FALSE) {
  ifelse(x==0, "0", 
  ifelse(x < 0.01 & thou==TRUE, "<0.01", 
  ifelse(x < 0.1 & thou==FALSE, "<0.1", 
  ifelse(signif(x, 2) < 1 & thou==TRUE, formatC(round(x,3), format='f', digits=3),
  ifelse(signif(x, 2) < 1, formatC(round(x,2), format='f', digits=2), 
  ifelse(signif(x, 2) < 10, formatC(round(x,2), format='f', digits=1),
  ifelse(x > 1 & rates==FALSE, formatC(signif(x, 2), big.mark=" ", format='d'), 
  ifelse(signif(x, 3) < 100, formatC(signif(x, 2), big.mark=" ", format='d'), formatC(signif(x, 3), big.mark=" ", format='d')))))))))
}
于 2012-06-26T08:46:15.763 回答