我正在尝试使用 MVVM Light 在我的应用程序中应用 MVVM 模式。我有一个数据绑定的列表框...
MainView.xaml [摘录]
<ListBox Name="recipesListBox"
ItemsSource="{Binding RecipeList}"
SelectedItem="{Binding SelectedRecipe, Mode=TwoWay}"
HorizontalAlignment="Stretch"
VerticalAlignment="Stretch"
Grid.Row="1"
Margin="12,0,12,0"
SelectionChanged="recipesListBox_SelectionChanged" >
MainViewModel.cs [摘录]
private Recipe selectedRecipe;
public Recipe SelectedRecipe
{
get
{
return selectedRecipe;
}
set
{
selectedRecipe = value;
RaisePropertyChanged("SelectedRecipe");
}
}
...在 SelectionChanged 上执行页面导航:
MainView.xaml.cs [摘录]
private void recipesListBox_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
string destination = "/RecipeView.xaml";
if (recipesListBox.SelectedIndex == -1) // If selected index is -1 (no selection) do nothing
return;
this.NavigationService.Navigate(new Uri(destination, UriKind.Relative));
//recipesListBox.SelectedIndex = -1; // Reset selected index to -1 (no selection)
}
//之后,您可以看到在页面导航后重置索引的旧代码 - 现在,使用绑定数据,显然它也将我的选定项目设置为 null!我该如何导航到新视图,显示所选项目的属性并在我返回时重置所选索引?谢谢!