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我正在尝试使用 eventmachine 和 em-synchrony 编写解析器(解析邮政编码的街道和房屋)。问题是我要解析的网站具有嵌套结构——每个邮政编码都有许多街道页面,这些页面具有分页。所以算法很简单:

  • 对于每个邮政编码
    • 访问邮政编码索引页面
      • 解析索引页面
      • 解析分页
      • 对于每个分页页面解析此页面

这是一个这样的解析器的例子(它有效):

require "nokogiri"
require "em-synchrony"
require "em-synchrony/em-http"

def url page = nil
  url = "http://gistflow.com/all"
  url << "?page=#{page}" if page
  url
end

EM.synchrony do
  concurrency = 2

  # here [1] is array of index pages, for this template let it be just [1]
  results = EM::Synchrony::Iterator.new([1], concurrency).map do |index, iter|
    index_page = EM::HttpRequest.new(url).aget

    index_page.callback do
      # here we make some parsing and find out wheter index page 
      # has pagination. The worst case is that it has pagination
      pages = [2,3,4,5]

      unless pages.empty?
        # here we need to parse all pages
        # with urls like url(page)
        # how can I do it more efficiently?
      end

      iter.return "SUCC #{index}"
    end

    index_page.errback do 
      iter.return "ERR #{index}"
    end
  end

  p results
  EM.stop
end

所以诀窍就在这个块里面:

unless pages.empty?
  # here we need to parse all pages
  # with urls like url(page)
  # how can I do it more efficiently?
end

如何在同步迭代器循环中实现嵌套的 EM HTTP 调用?

我尝试了不同的方法,但每次我遇到诸如“无法从根光纤产生”或调用 errback 块之类的错误时。

4

1 回答 1

2

一种解决方案是使用FiberIterator和同步.get而不是.aget

require "em-synchrony"
require "em-synchrony/em-http"
require "em-synchrony/fiber_iterator"

def url page = nil
  url = "http://gistflow.com/all"
  url << "?page=#{page}" if page
  url
end

EM.synchrony do
  concurrency = 2

  master_pages = [1,2,3,4]

  EM::Synchrony::FiberIterator.new(master_pages, concurrency).each do |iter|
    result = EM::HttpRequest.new(url).get
    if result
      puts "SUCC #{iter}"
      detail_pages = [1,2,3,4]       
      EM::Synchrony::FiberIterator.new(detail_pages, concurrency).each do |iter2|
        result2 = EM::HttpRequest.new(url).get
        puts "SUCC/ERR #{iter} > #{iter2}"
      end
    else
      puts "ERR #{iter}"
    end
  end

  EM.stop

end
于 2012-06-19T16:25:28.173 回答