您可以尝试更改生成的代码。这样就返回了一个不同的视图。但是,如果您不返回视图,我希望 EF 会失败。
这个想法是生成的类适用于 DBContext 中的所有集合。实际上,如果视图与您拥有的上下文不匹配(哈希比较),您将收到运行时错误。
例如
/// <Summary>
/// The constructor stores the views for the extents and also the hash values generated based on the metadata and mapping closure and views.
/// </Summary>
public ViewsForBaseEntitySets24F9763E92A9F77E970A08557E1855C7579989F684539A5FB429069F966B9B7B()
{
this.EdmEntityContainerName = "Ef6Ctx3";
this.StoreEntityContainerName = "CodeFirstDatabase";
this.HashOverMappingClosure = "d7686982aa7cffcf874313838914e93f78d4d7d6d345d19261ef5edc8b4e96dd";
this.HashOverAllExtentViews = "7b8857ee3ee44d13b2479e43c54dbdfb6bc8914e222c7891afcfcd9a29b06b2f";
this.ViewCount = 2;
}
但是对于给定的视图,您可以返回不同的字符串
/// <Summary>
/// return view for CodeFirstDatabase.pocotest
/// </Summary>
private System.Collections.Generic.KeyValuePair<string, string> GetView0()
{
return new System.Collections.Generic.KeyValuePair<string, string>("CodeFirstDatabase.pocotest", @"
SELECT VALUE -- Constructing pocotest
[CodeFirstDatabaseSchema.pocotest](T1.pocotest_Id, T1.pocotest_f1, T1.pocotest_f2, T1.pocotest_f2a, T1.pocotest_f3, T1.pocotest_f5, T1.pocotest_f6b)
FROM (
SELECT
T.Id AS pocotest_Id,
T.f1 AS pocotest_f1,
T.f2 AS pocotest_f2,
T.f2a AS pocotest_f2a,
T.f3 AS pocotest_f3,
T.f5 AS pocotest_f5,
T.f6b AS pocotest_f6b,
True AS _from0
FROM Ef6Ctx3.poco1s AS T
) AS T1");
}