通过 SOAP 方法，我想从 android/eclipse 使用 Web 服务。但是使用 Web 服务的方式是，我必须提供输入，并且它应该必须从 Web 服务返回正确的值。如何实现它？
网络方法
public class FahrenheitToCelsius {
public double FahrenheitToCelsius(double Fahrenheit)
{
return ((Fahrenheit - 32) * 5) / 9;
}
}
.java 类
public class Demo_webserviceActivity extends Activity
{
/** Called when the activity is first created. */
private static String NAMESPACE = "http://tempuri.org/";
private static String METHOD_NAME = "FahrenheitToCelsius";
private static String SOAP_ACTION = "http://tempuri.org/FahrenheitToCelsius";
private static String URL = "http://www.w3schools.com/webservices/tempconvert.asmx?WSDL";
Button btnFar;
EditText txtFar,txtCel;
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
btnFar = (Button)findViewById(R.id.btnFar);
txtFar = (EditText)findViewById(R.id.txtFar);
txtCel = (EditText)findViewById(R.id.txtCel);
btnFar.setOnClickListener(new View.OnClickListener()
{
public void onClick(View v)
{
//Initialize soap request + add parameters
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
//Use this to add parameters
request.addProperty("Fahrenheit",txtFar.getText().toString());
//Declare the version of the SOAP request
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
envelope.dotNet = true;
try
{
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
//this is the actual part that will call the webservice
androidHttpTransport.call(SOAP_ACTION, envelope);
// Get the SoapResult from the envelope body.
SoapObject result = (SoapObject)envelope.bodyIn;
if(result != null)
{
//Get the first property and change the label text
txtCel.setText(result.getProperty(0).toString());
}
else
{
Toast.makeText(getApplicationContext(), "No Response",Toast.LENGTH_LONG).show();
}
}
catch (Exception e)
{
e.printStackTrace();
}
}
});
}
}