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我目前正在编写一个 Powershell 脚本，用于从 Active Directory 中选择用户，然后允许您选择他们已登录的计算机（通过 SQL 查询）和远程桌面。提示用户输入全名或部分名称，然后打印所有匹配项的列表，并提示他们选择一个。所有匹配项的列表来自遍历一个数组，所有匹配项都已分配给该数组。如果从名称输入中搜索产生一个只有一个人的数组，然后用户选择那个人，我会收到以下错误：

    Get-ADUser : Variable: 'u' found in expression: $u is not defined.
    At C:\Users\styanc\Desktop\test.ps1:67 char:12
    +     Get-ADUser <<<<  -f{DisplayName -eq $u} -Properties TelephoneNumber, OtherTelephone, Mobile | Select TelephoneNumber, OtherTelephone, Moblie #| Format
    -List
        + CategoryInfo          : InvalidArgument: (:) [Get-ADUser], ArgumentException
        + FullyQualifiedErrorId : Variable: 'u' found in expression: $u is not defined.,Microsoft.ActiveDirectory.Management.Commands.GetADUser
The functions are as follows.
    Function FindUsers{
        param ($n)
        #creates an array of users with names LIKE the script users input
        $n = @(Get-ADUser -f {DisplayName -like $n} -Properties DisplayName) 
        return $n
    }
    Function PrintUsers{
        param ($array)
        $i = 1
        #for each user in the array, print their name
        foreach($object in $array){
            Write-Host "$i. $($object.name)"
            $i++
        }
    }
    Function SelectUser{
        #there's probably a better way to do newlines?
        Write-Host ""
        #user selects a user from the list by number, input needs validation
        $userNum = Read-Host "Please select a user. (by number)"
        $length = $usersArray.Length
        Write-Host $length
        Write-Host $usersArray.length
        if($usersArray.Length -eq $null){
            $user = ($usersArray.Name)
        }
        else{
            $user = ($usersArray[$userNum-1].Name)
        }
        #$user = ($usersArray[$userNum-1].Name)
        return $user
    }

并被称为：

$usersArray = FindUsers -n $name
PrintUsers -array $usersArray
$selectedUser = SelectUser
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1 回答 1

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在函数FindUsers中，只需尝试替换：

return $n

经过

return ,$n

,$nforcereturn命令返回一个列表，无论$n是单个值还是列表，如果没有返回命令，则习惯于将单个值数组转换为单个值。

于 2012-06-12T06:53:19.200 回答