正如Brian Warshaw在这里所说的,它只是一个实现try
和finally
块,以确保对象被释放。除了他的回答之外,using
block 还确保即使您使用scope返回内部,该对象也已被处置。
我自己曾经对此感到好奇,并使用以下方法对其进行了测试:
自定义 IDisposable 测试类和 Main
private class DisposableTest : IDisposable
{
public string Name { get; set; }
public void Dispose() { Console.WriteLine("{0}.Dispose() is called !", Name); }
}
public static void Main(string[] args)
{
try
{
UsingReturnTest();
UsingExceptionTest();
}
catch { }
try
{
DisposeReturnTest();
DisposeExceptionTest();
}
catch { }
DisposeExtraTest();
Console.ReadLine();
}
测试用例实现
private static string UsingReturnTest()
{
using (DisposableTest usingReturn = new DisposableTest() { Name = "UsingReturn" })
{
return usingReturn.Name;
}
}
private static void UsingExceptionTest()
{
using (DisposableTest usingException = new DisposableTest() { Name = "UsingException" })
{
int x = int.Parse("NaN");
}
}
private static string DisposeReturnTest()
{
DisposableTest disposeReturn = new DisposableTest() { Name = "DisposeReturn" };
return disposeReturn.Name;
disposeReturn.Dispose(); // # IDE Warning; Unreachable code detected
}
private static void DisposeExceptionTest()
{
DisposableTest disposeException = new DisposableTest() { Name = "DisposeException" };
int x = int.Parse("NaN");
disposeException.Dispose();
}
private static void DisposeExtraTest()
{
DisposableTest disposeExtra = null;
try
{
disposeExtra = new DisposableTest() { Name = "DisposeExtra" };
return;
}
catch { }
finally
{
if (disposeExtra != null) { disposeExtra.Dispose(); }
}
}
输出是:
- UsingReturn.Dispose() 被调用!
- UsingException.Dispose() 被调用!
- DisposeExtra.Dispose() 被调用!