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我正在使用实体框架开发一个更大的系统。就个人而言,我确实喜欢用于编写 LINQ/ESQL 查询的基于方法的语法。

但我不知道如何正确编写以下连接查询。

假设,我有以下实体类和 DbContext 存储库:

public class A
{
    [Key]
    public int ID{get;set;}
    public virtual ICollection<B> BCollection { get; set; }
}
public class B
{
    [Key]
    public int ID { get; set; }
    public virtual A A { get; set; }
    public virtual ICollection<C> CCollection { get; set; }
    public virtual ICollection<D> DCollection { get; set; }
}
public class C
{
    [Key]
    public int ID { get; set; }
    public virtual B B { get; set; }
}
public class D
{
    [Key]
    public int ID { get; set; }
    public virtual B B { get; set; }
}
public class Entities : DbContext
{
    public DbSet<A> SetA { get; set; }
    public DbSet<B> SetB { get; set; }
    public DbSet<C> SetC { get; set; }
    public DbSet<D> SetD { get; set; }
}

现在我想得到“整个”树:A类的所有项目,以及它们附加的B类项目,其中B类的每个项目都配备了C类和D类的项目。

我可以用这个查询来做到这一点:

var x = db.SetA
            .Include(a => a.BCollection.Select(b => b.CCollection))
            .Include(a => a.BCollection.Select(b => b.DCollection))
            .ToList();

但我认为这可以更容易地完成,对吧?

请注意:我确实想急切加载整个树,因为我不想使用延迟加载。

编辑:

这不是一个关于单个问题的问题,我的问题更多是关于方法。当我编写如上所示的查询时,EF 会生成一个巨大的查询:

 SELECT [Project3].[ID] AS [ID],
   [Project3].[C9] AS [C1],
   [Project3].[C2] AS [C2],
   [Project3].[C3] AS [C3],
   [Project3].[C4] AS [C4],
   [Project3].[C1] AS [C5],
   [Project3].[C5] AS [C6],
   [Project3].[C6] AS [C7],
   [Project3].[C7] AS [C8],
   [Project3].[C8] AS [C9]
FROM   (SELECT [Extent1].[ID]     AS [ID],
           [UnionAll1].[C1]   AS [C1],
           [UnionAll1].[ID]   AS [C2],
           [UnionAll1].[ID1]  AS [C3],
           [UnionAll1].[A_ID] AS [C4],
           [UnionAll1].[ID2]  AS [C5],
           [UnionAll1].[B_ID] AS [C6],
           [UnionAll1].[C2]   AS [C7],
           [UnionAll1].[C3]   AS [C8],
           CASE
             WHEN ([UnionAll1].[ID] IS NULL) THEN CAST(NULL AS int)
             ELSE 1
           END                AS [C9]
    FROM   [dbo].[A] AS [Extent1]
           OUTER APPLY (SELECT CASE
                                 WHEN ([Extent3].[ID] IS NULL) THEN CAST(NULL AS int)
                                 ELSE 1
                               END               AS [C1],
                               [Extent2].[ID]    AS [ID],
                               [Extent2].[ID]    AS [ID1],
                               [Extent2].[A_ID]  AS [A_ID],
                               [Extent3].[ID]    AS [ID2],
                               [Extent3].[B_ID]  AS [B_ID],
                               CAST(NULL AS int) AS [C2],
                               CAST(NULL AS int) AS [C3]
                        FROM   [dbo].[B] AS [Extent2]
                               LEFT OUTER JOIN [dbo].[C] AS [Extent3]
                                 ON [Extent2].[ID] = [Extent3].[B_ID]
                        WHERE  [Extent1].[ID] = [Extent2].[A_ID]
                        UNION ALL


                        SELECT 2                 AS [C1],
                               [Extent4].[ID]    AS [ID],
                               [Extent4].[ID]    AS [ID1],
                               [Extent4].[A_ID]  AS [A_ID],
                               CAST(NULL AS int) AS [C2],
                               CAST(NULL AS int) AS [C3],
                               [Extent5].[ID]    AS [ID2],
                               [Extent5].[B_ID]  AS [B_ID]
                        FROM   [dbo].[B] AS [Extent4]
                               INNER JOIN [dbo].[D] AS [Extent5]
                                 ON [Extent4].[ID] = [Extent5].[B_ID]
                        WHERE  [Extent1].[ID] = [Extent4].[A_ID]) AS [UnionAll1]) AS [Project3]
ORDER  BY [Project3].[ID] ASC,
      [Project3].[C9] ASC,
      [Project3].[C3] ASC,
      [Project3].[C1] ASC

但实际上我自己会写的是这样的:

SELECT     *
FROM         D RIGHT OUTER JOIN
                  B ON D.B_ID = B.ID LEFT OUTER JOIN
                  C ON B.ID = C.B_ID RIGHT OUTER JOIN
                  A ON B.A_ID = A.ID

我希望这有助于澄清我的问题。重点是:如何让实体框架生成更高效的查询?

4

1 回答 1

1

我认为以下 LINQ 会生成您正在寻找的“大型”查询:

    var query =
        db.SetA
            .Join(db.SetB, a => a, b => b.A, (a, b) => new
                                                           {
                                                               A = a,
                                                               B = b
                                                           })
            .Join(db.SetC, ab => ab.B, c => c.B, (ab, c) => new
                                                                {
                                                                    A = ab.A,
                                                                    B = ab.B,
                                                                    C = c
                                                                })
            .Join(db.SetD, abc => abc.B, d => d.B, (abc, d) => new
                                                                   {
                                                                       A = abc.A,
                                                                       B = abc.B,
                                                                       C = abc.C,
                                                                       D = d
                                                                   });

    foreach (var abcd in query)
    {
        Console.WriteLine("{0}-{1}-{2}-{3}", abcd.A.ID, abcd.B.ID, abcd.C.ID, abcd.D.ID);
    }
于 2012-06-12T10:10:30.780 回答