我的应用程序中有一个用于登录身份验证的警报对话框。在发送请求时,我想显示一个进度条,如果响应成功则想关闭。如果有人知道,请帮助我。我使用以下代码:
final AlertDialog.Builder alert = new AlertDialog.Builder(this);
LinearLayout login = new LinearLayout(this);
TextView tvUserName = new TextView(this);
TextView tvPassword = new TextView(this);
TextView tvURL = new TextView(this);
final EditText etUserName = new EditText(this);
final EditText etPassword = new EditText(this);
final EditText etURL = new EditText(this);
login.setOrientation(1); // 1 is for vertical orientation
tvUserName.setText(getResources().getString(R.string.username));
tvPassword.setText(getResources().getString(R.string.password));
tvURL.setText("SiteURL");
login.addView(tvURL);
login.addView(etURL);
login.addView(tvUserName);
login.addView(etUserName);
login.addView(tvPassword);
etPassword.setInputType(InputType.TYPE_CLASS_TEXT
| InputType.TYPE_TEXT_VARIATION_PASSWORD);
login.addView(etPassword);
alert.setView(login);
alert.setTitle(getResources().getString(R.string.login));
alert.setCancelable(true);
alert.setPositiveButton(getResources().getString(R.string.login),
new DialogInterface.OnClickListener() {
public void onClick(final DialogInterface dialog,
int whichButton) {
strhwdXml = etURL.getText().toString();
strUserName = etUserName.getText().toString();
XmlUtil.username = strUserName;
strPassword = etPassword.getText().toString();
if ((strUserName.length() == 0)
&& (strPassword.length() == 0)
&& (strhwdXml.length() == 0)) {
Toast.makeText(
getBaseContext(),
getResources().getString(
R.string.userPassword),
Toast.LENGTH_SHORT).show();
onStart();
} else {
final SharedPreferences prefs = PreferenceManager
.getDefaultSharedPreferences(getApplicationContext());
SharedPreferences.Editor prefsEditor = prefs
.edit();
try {
StringBuffer inStreamBuf = new StringBuffer();
inStreamBuf = XmlUtil
.getLoginAuthResponse(strUserName,
strPassword, strhwdXml);
strXmlResponse = inStreamBuf.toString();
Log.e("Response:", strXmlResponse);
String parsedXML = ParseResponse(strXmlResponse);
if (parsedXML
.equalsIgnoreCase(getResources()
.getString(R.string.success))) {
}