1

给定以下json：

{ "response": {
"totalProcessingTime": "271.0",
"resultSets": {
    "products": {
        "firstHit": "1",
        "lastHit": "10",
        "totalHits": "77",
        "hits": [ 
            {   
                "number": "1",
                "dmsubcategory": "TV, lyd og bilde",
                "collection": "tilbud",
                "title": "<b>TV</b> Panasonic 47 TX-LU 7ET5Y"
            },
            {   
                "number": "2",
                "dmsubcategory": "TV, lyd og bilde",
                "collection": "tilbud",
                "title": "<b>TV</b> Panasonic 47 TX-LU 7ET5Y"
            },
            {   
                "number": "3",
                "dmsubcategory": "TV, lyd og bilde",
                "collection": "tilbud",
                "title": "<b>TV</b> Panasonic 47 TX-LU 7ET5Y"
            }
            ]
        }
    }
  }
}

我正在使用以下代码调用杰克逊：

ObjectMapper mapper = new ObjectMapper();
SearchResult searchResult = mapper.readValue(new URL(jsonUrl + queryUrl), SearchResult.class);

我已经为产品类看起来像的整个层次结构收集了 POJO：

public class Products {

public List<Hits> hits;
public String totalHits;

@JsonAnySetter
public void handleUnknown(String key, Object value) {
    // do something: put to a Map; log a warning, whatever
}

public List<Hits> getHits() {
    return hits;
}

public void setHits(List<Hits> hits) {
    this.hits = hits;
}

public String getTotalHits() {
    return totalHits;
}

public void setTotalHits(String totalHits) {
    this.totalHits = totalHits;
}

}

和命中类：

public class Hits {

public String number;
public String title;

public String getNumber() {
    return number;
}
public void setNumber(String number) {
    this.number = number;
}
public String getTitle() {
    return title;
}
public void setTitle(String title) {
    this.title = title;
}

@JsonAnySetter
public void handleUnknown(String key, Object value) {
    // do something: put to a Map; log a warning, whatever
}

}

所有其他属性都映射正确，但不是包含命中的列表。都是空的。我怎样才能映射它以使其正确？

谢谢！

4

2 回答 2

5

您的型号不兼容。

为了看看出了什么问题，也许有一些 toStrings 是个好主意，你可以很容易地看到映射失败的地方。

您有一个需要保存属性响应的对象，需要保存属性 resultSets 需要保存需要保存命中的属性 products。

我是这样实现的：

GeneralResponse
  - Response
    - ResultSets
      - Products
        - Hits
          - number
          - title

请测试以下实现：

package snippet;

public class GeneralResponse {

    private Response response;

    public Response getResponse() {
        return response;
    }

    public void setResponse(Response response) {
        this.response = response;
    }

    @Override
    public String toString() {
        return "GeneralResponse [response=" + response + "]";
    }

}


package snippet;

public class ResultSets {

    private Products products;

    public Products getProducts() {
        return products;
    }

    public void setProducts(Products products) {
        this.products = products;
    }

    @Override
    public String toString() {
        return "ResultSets [products=" + products + "]";
    }

}

package snippet;

import java.util.List;

import org.codehaus.jackson.annotate.JsonAnySetter;

public class Products {

    public List<Hits> hits;
    public String totalHits;

    @JsonAnySetter
    public void handleUnknown(String key, Object value) {
        // do something: put to a Map; log a warning, whatever
    }

    public List<Hits> getHits() {
        return hits;
    }

    public void setHits(List<Hits> hits) {
        this.hits = hits;
    }

    public String getTotalHits() {
        return totalHits;
    }

    public void setTotalHits(String totalHits) {
        this.totalHits = totalHits;
    }

    @Override
    public String toString() {
        return "Products [hits=" + hits + ", totalHits=" + totalHits + "]";
    }

}


package snippet;

import org.codehaus.jackson.annotate.JsonAnySetter;

public class Response {

    private ResultSets resultSets;

    public ResultSets getResultSets() {
        return resultSets;
    }

    public void setResultSets(ResultSets resultSets) {
        this.resultSets = resultSets;
    }

    @Override
    public String toString() {
        return "Response [resultSets=" + resultSets + "]";
    }

    @JsonAnySetter
    public void handleUnknown(String key, Object value) {
        // do something: put to a Map; log a warning, whatever
    }

}



package snippet;

import org.codehaus.jackson.annotate.JsonAnySetter;

public class Hits {

    public String number;
    public String title;

    public String getNumber() {
        return number;
    }

    public void setNumber(String number) {
        this.number = number;
    }

    public String getTitle() {
        return title;
    }

    public void setTitle(String title) {
        this.title = title;
    }

    @JsonAnySetter
    public void handleUnknown(String key, Object value) {
        // do something: put to a Map; log a warning, whatever
    }

    @Override
    public String toString() {
        return "Hits [number=" + number + ", title=" + title + "]";
    }

}

毕竟你可以做这样的事情：

    ObjectMapper om = new ObjectMapper();
    Object r = om.readValue(inputStream, GeneralResponse.class);
于 2012-06-11T07:41:09.333 回答
0

代码看起来不错。错误可能在json响应中

"title": "<b>TV</b> Panasonic 47”TX-LU 7ET5Y"

47 之后和 TX 之前的反引号可能很麻烦。请检查您是否可以解析此响应。

于 2012-06-11T07:28:57.467 回答