Traceback (most recent call last):
File "manage.py", line 10, in <module>
execute_from_command_line(sys.argv)
File "D:\PythonPack\lib\site-packages\django\core\management\__init__.py", lin
e 443, in execute_from_command_line
utility.execute()
File "D:\PythonPack\lib\site-packages\django\core\management\__init__.py", lin
e 382, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "D:\PythonPack\lib\site-packages\django\core\management\base.py", line 19
6, in run_from_argv
self.execute(*args, **options.__dict__)
File "D:\PythonPack\lib\site-packages\django\core\management\base.py", line 23
2, in execute
output = self.handle(*args, **options)
File "D:\PythonPack\lib\site-packages\django\core\management\base.py", line 37
1, in handle
return self.handle_noargs(**options)
File "D:\PythonPack\lib\site-packages\django\core\management\commands\syncdb.p
y", line 57, in handle_noargs
cursor = connection.cursor()
File "D:\PythonPack\lib\site-packages\django\db\backends\__init__.py", line 30
6, in cursor
cursor = self.make_debug_cursor(self._cursor())
File "D:\PythonPack\lib\site-packages\django\db\backends\sqlite3\base.py", lin
e 281, in _cursor
self._sqlite_create_connection()
File "D:\PythonPack\lib\site-packages\django\db\backends\sqlite3\base.py", lin
e 271, in _sqlite_create_connection
self.connection = Database.connect(**kwargs)
sqlite3.OperationalError: unable to open database file
尝试后我遇到了这些错误
python manage.py syncbd
在本教程中 https://docs.djangoproject.com/en/dev/intro/tutorial01/
使用 Django 启动第一个 Web 应用程序(Dian-go 或 Jan-go ?)。有人可以帮助我导致这些错误消息的原因吗?
更新
DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3', # Add 'postgresql_psycopg2', 'mysql', 'sqlite3' or 'oracle'.
'NAME': 'D:\Python\mysite\sqlitedb', # Or path to database file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for default. Not used with sqlite3.
}
}
那是数据库设置