php - 使用 PHP 显示 JSON 数据

Question

我有以下数组

"forecast":{
    "txt_forecast": {
    "date":"11:00 PM EDT",
    "forecastday": [
    {
    "period":0,
    "icon":"partlycloudy",
    "icon_url":"http://icons-ak.wxug.com/i/c/k/partlycloudy.gif",
    "title":"Saturday",
    "fcttext":"Partly cloudy in the morning, then mostly cloudy. High of 88F. Winds from the South at 5 to 10 mph.",
    "fcttext_metric":"Partly cloudy in the morning, then mostly cloudy. High of 31C. Winds from the South at 10 to 15 km/h.",
    "pop":"0"
    }
    ,
    {
    "period":1,
    "icon":"partlycloudy",
    "icon_url":"http://icons-ak.wxug.com/i/c/k/partlycloudy.gif",
    "title":"Saturday Night",
    "fcttext":"Overcast in the evening, then partly cloudy. Low of 64F. Winds less than 5 mph.",
    "fcttext_metric":"Overcast in the evening, then partly cloudy. Low of 18C. Winds less than 5 km/h.",
    "pop":"10"
    }

我将如何在 PHP 中显示信息？它一直持续到第 7 期。

编辑：这是我编辑的代码不起作用。

<?php
$json_string =    file_get_contents("http://api.wunderground.com/api/7ec5f6510a4656df/geolookup/forecast/q/40121.json");
$parsed_json = json_decode($json_string);
$temp = $parsed_json->{'forecast'}->{'txt_forecast'}->{'date'};
$title = $parsed_json->{'forecast'}->{'txt_forecast'}->{'forecastday'}->{'title'};
$for = $parsed_json->{'forecast'}->{'txt_forecast'}->{'forecastday'}->{'fcttext'};
echo "Current date is ${temp},  ${title}: ${for}\n";

foreach($parsed_json['forecast']['forecastday[0]'] as $key => $value)
{
   echo $value['period'];
   echo $value['icon'];
   // etc
}
?>

Answer 1

更新

$json_string =    file_get_contents("http://api.wunderground.com/api/7ec5f6510a4656df/geolookup/forecast/q/40121.json");
$parsed_json = json_decode($json_string, true);
$parsed_json = $parsed_json['forecast']['txt_forecast']['forecastday'];
//pr($parsed_json);

foreach($parsed_json as $key => $value)
{
   echo $value['period'] . '<br>';
   echo $value['icon'] . '<br>';
   // etc
}

结果：

0
chancetstorms
1
tstorms
2
tstorms
3
tstorms
4
tstorms
5
partlycloudy
6
partlycloudy
7
partlycloudy

---

您将不得不为此使用json_decode()功能。

$myArray = json_decode($yourJSON, true);

现在您可以使用foreach从$myArray数组中获取数据，例如：

foreach($myArray['forecast']['forecastday'] as $key => $value)
{
   echo $value['period'];
   echo $value['icon'];
   // etc
}

Answer 2

您还可以将 json 转换为 PHP 对象：

$myData = json_decode($yourJSON);

foreach($myData->forecast->forecastday as $day) {
   echo $day->period;
   echo $day->icon;
}

---

编辑：

我认为您可以使用以下方法修复问题中的代码：

<?php
$json_string =    file_get_contents("http://api.wunderground.com/api/7ec5f6510a4656df/geolookup/forecast/q/40121.json");
$parsed_json = json_decode($json_string);
$forecast = $parsed_json->forecast->txt_forecast;
$temp = $forecast->date;
$title = $forecast->forecastday->title;
$for = $forecast->forecastday->fcttext;
echo "Current date is ${temp},  ${title}: ${for}\n";

foreach($forecast->forecastday as $value) {
   echo $value['period'];
   echo $value['icon'];
   // etc
}
?>