<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>ajax div example</title>
<script type="text/javascript" src="jscripts/jquery-1.6.4.min.js"></script>
<script type="text/javascript">
var dbn,machine_name;
function main_draw(d,m,r)
{
dbn = d;
machine_name = m;
draw_charts();
if ( r > 0 )
{
setRefreshid = setInterval("draw_pie()",r);
}
}
function draw_charts()
{
document.getElementById('ajdiv4').innerHTML = "";
document.getElementById('ajdiv3').innerHTML = "";
document.getElementById('ajdiv2').innerHTML = "";
document.getElementById('ajdiv1').innerHTML = "";
draw_pie();
draw_line();
draw_space();
draw_backup();
}
function draw_pie()
{
setTimeout(function() {
$.ajax( {
url: 'JSCharts/graph_pie1.html',
success: function(html)
{
$("#ajdiv4").html(html);
}
}); }, 100);
}
function draw_line()
{
setTimeout(function() {
$.ajax( {
url: 'JSCharts/graph_line1.html',
success: function(html)
{
$("#ajdiv3").html(html);
}
}); }, 200);
}
function draw_space()
{
setTimeout(function() {
$.ajax( {
url: 'JSCharts/space_graph.php',
success: function(html)
{
$("#ajdiv2").html(html);
}
}); }, 300);
}
function draw_backup()
{
setTimeout(function() {
$.ajax( {
url: 'JSCharts/backup_graph.php',
success: function(html)
{
$("#ajdiv1").html(html);
}
}); }, 400);
}
</script>
</head>
<body>
<div id="ajdiv1" style="float:left"></div>
<div id="ajdiv2" style="float:left"></div>
<div id="ajdiv3" style="float:left"></div>
<div id="ajdiv4" style="float:left"></div>
<button id="b1" onclick="main_draw('CQ1','va2apsap010',10000)">Display Content</button>
</body>
</html>
上面是一个完整的代码,它在单击“显示内容”时调用 AJAX,然后通过调用函数“draw_pie”刷新 div“ajdiv4”的内容。唯一的问题是,当它刷新时,它会将饼图一直向左移动。我希望它留在当前位置并更新它。如果有人知道这里发生了什么,请帮忙,谢谢。