2

我有一个地方类定义如下：

    public class place
    {
            public string placeID { get; set; }
            public string placeCatID { get; set; }
            public string placeName { get; set; }
    }

并将数据存储在列表调用 placelist 中

    List<place> placelist = new List<place>();

可以指导我如何将位置列表转换为字符串或将其导出并保存为 XML 文件格式，如下所示：

    <place>
            <pID>0001</pID>
            <pCatID>C1</pID>
            <pName>Location 1</pName>
    </place>
    <place>
            <pID>0002</pID>
            <pCatID>C1</pID>
            <pName>Location 2</pName>
    </place>

使用的语言是 C#

谢谢。

4

5 回答 5

4

您可以使用任何序列化为 XML 的序列化程序。我会建议 DataContractSerializer

来自 MSDN：

DataContractSerializer s = new DataContractSerializer(typeof(T));
    using (FileStream fs = File.Open("test" + typeof(T).Name + ".xml", FileMode.Create))
    {
        Console.WriteLine("Testing for type: {0}", typeof(T)); 
        s.WriteObject(fs, obj);
    }

http://msdn.microsoft.com/en-us/library/bb675198.aspx

在您的情况下，将 T 替换为List<T>

于 2012-06-09T02:54:00.153 回答
2

简而言之，可以使用以下选项：

于 2012-06-09T02:58:14.423 回答
2

以下解决方案适用于XmlSerializer但您也可以使用DataContractSerializer。 XmlSerializer默认情况下序列化所有字段，DataContractSerializer您需要明确指定要序列化的内容。

添加序列化属性以具有自定义元素名称：

public class place
{
    [XmlElement("pID")]
    public string placeID { get; set; }
    [XmlElement("pCatID")]
    public string placeCatID { get; set; }
    [XmlElement("pName")]
    public string placeName { get; set; }
}

序列化代码：

var ser = new XmlSerializer(typeof(List<place>));
TextWriter writer = new StreamWriter(@"C:\1.xml");
// o is List<place> here
ser.Serialize(writer, o);

XML:

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfPlace xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <place>
    <pID>1</pID>
    <pCatID>2</pCatID>
    <pName>3</pName>
  </place>
  <place>
    <pID>3</pID>
    <pCatID>4</pCatID>
    <pName>5</pName>
  </place>
</ArrayOfPlace>
于 2012-06-09T03:14:41.300 回答
0

我刚刚写了一篇关于将对象数据保存为 Binary、XML 或 Json 的博文。因为您希望类变量在 xml 文件中的名称与它们在代码中的名称不同，所以您需要使用 [XmlElement("NameToShowUpInXmlFileGoesHere")] 来装饰每个公共属性。

一旦你有了它，只需调用以下函数来保存对象实例并将其加载到文件中/从文件中加载。

注意：这需要将 System.Xml 程序集包含在您的项目中。

/// <summary>
/// Writes the given object instance to an XML file.
/// <para>Only Public properties and variables will be written to the file. These can be any type though, even other classes.</para>
/// <para>If there are public properties/variables that you do not want written to the file, decorate them with the [XmlIgnore] attribute.</para>
/// <para>Object type must have a parameterless constructor.</para>
/// </summary>
/// <typeparam name="T">The type of object being written to the file.</typeparam>
/// <param name="filePath">The file path to write the object instance to.</param>
/// <param name="objectToWrite">The object instance to write to the file.</param>
/// <param name="append">If false the file will be overwritten if it already exists. If true the contents will be appended to the file.</param>
public static void WriteToXmlFile<T>(string filePath, T objectToWrite, bool append = false) where T : new()
{
    TextWriter writer = null;
    try
    {
        var serializer = new XmlSerializer(typeof(T));
        writer = new StreamWriter(filePath, append);
        serializer.Serialize(writer, objectToWrite);
    }
    finally
    {
        if (writer != null)
            writer.Close();
    }
}

/// <summary>
/// Reads an object instance from an XML file.
/// <para>Object type must have a parameterless constructor.</para>
/// </summary>
/// <typeparam name="T">The type of object to read from the file.</typeparam>
/// <param name="filePath">The file path to read the object instance from.</param>
/// <returns>Returns a new instance of the object read from the XML file.</returns>
public static T ReadFromXmlFile<T>(string filePath) where T : new()
{
    TextReader reader = null;
    try
    {
        var serializer = new XmlSerializer(typeof(T));
        reader = new StreamReader(filePath);
        return (T)serializer.Deserialize(reader);
    }
    finally
    {
        if (reader != null)
            reader.Close();
    }
}

例子

public class place
{
    [XmlElement("pID")]
    public string placeID { get; set; }
    [XmlElement("pCatID")]
    public string placeCatID { get; set; }
    [XmlElement("pName")]
    public string placeName { get; set; }
}

// To write the placeList variable contents to XML.
WriteToXmlFile<List<place>>("C:\places.txt", placeList);

// To read the xml file contents back into a variable.
List<place> placeList= ReadFromXmlFile<List<place>>("C:\places.txt");
于 2014-03-14T22:50:09.870 回答
0

您可以编写自己的ToXml()方法或使用DataContractSerializer.

于 2012-06-09T02:51:48.070 回答