11

因此，我已经阅读了在 Scrapy 中使用经过身份验证的会话的 Crawling并且我挂断了，我 99% 确定我的解析代码是正确的，我只是不相信登录正在重定向并成功。

我也遇到了 check_login_response() 的问题，不确定它正在检查哪个页面。虽然“退出”是有道理的。




====== 已更新 ======

from scrapy.contrib.spiders.init import InitSpider
from scrapy.http import Request, FormRequest
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from scrapy.contrib.spiders import Rule

from scrapy.spider import BaseSpider
from scrapy.selector import HtmlXPathSelector

from linkedpy.items import LinkedPyItem

class LinkedPySpider(InitSpider):
    name = 'LinkedPy'
    allowed_domains = ['linkedin.com']
    login_page = 'https://www.linkedin.com/uas/login'
    start_urls = ["http://www.linkedin.com/csearch/results?type=companies&keywords=&pplSearchOrigin=GLHD&pageKey=member-home&search=Search#facets=pplSearchOrigin%3DFCTD%26keywords%3D%26search%3DSubmit%26facet_CS%3DC%26facet_I%3D80%26openFacets%3DJO%252CN%252CCS%252CNFR%252CF%252CCCR%252CI"]

    def init_request(self):
        #"""This function is called before crawling starts."""
        return Request(url=self.login_page, callback=self.login)

    def login(self, response):
        #"""Generate a login request."""
        return FormRequest.from_response(response,
                    formdata={'session_key': 'user@email.com', 'session_password': 'somepassword'},
                    callback=self.check_login_response)

    def check_login_response(self, response):
        #"""Check the response returned by a login request to see if we aresuccessfully logged in."""
        if "Sign Out" in response.body:
            self.log("\n\n\nSuccessfully logged in. Let's start crawling!\n\n\n")
            # Now the crawling can begin..

            return self.initialized() # ****THIS LINE FIXED THE LAST PROBLEM*****

        else:
            self.log("\n\n\nFailed, Bad times :(\n\n\n")
            # Something went wrong, we couldn't log in, so nothing happens.

    def parse(self, response):
        self.log("\n\n\n We got data! \n\n\n")
        hxs = HtmlXPathSelector(response)
        sites = hxs.select('//ol[@id=\'result-set\']/li')
        items = []
        for site in sites:
            item = LinkedPyItem()
            item['title'] = site.select('h2/a/text()').extract()
            item['link'] = site.select('h2/a/@href').extract()
            items.append(item)
        return items



通过在 self.initialized() 前面添加“Return”解决了该问题

再次感谢！-标记

4

1 回答 1

4 
class LinkedPySpider(BaseSpider):

应该：

class LinkedPySpider(InitSpider):

此外，您不应该覆盖parse我在此处的回答中提到的功能：https ://stackoverflow.com/a/5857202/crawling-with-an-authenticated-session-in-scrapy

如果您不了解如何定义提取链接的规则，只需正确阅读文档：
http://readthedocs.org/docs/scrapy/en/latest/topics/spiders.html#scrapy.contrib。 spiders.Rule
http://readthedocs.org/docs/scrapy/en/latest/topics/link-extractors.html#topics-link-extractors

于 2012-06-08T18:22:12.880 回答