8 
// BOOST Includes
#include <boost/assign.hpp>             // Boost::Assign
#include <boost/assign/list_of.hpp>     // Boost::Assign::List_Of
#include <boost/assign/std/map.hpp>     // Boost::Assign::Map_List_Of
#include <boost/tuple/tuple.hpp>        // Boost::Tuples
// STD Includes
#include <map>
#include <vector>
#include <string>
// Using namespaces
using namespace std;
using namespace boost;
using namespace boost::assign;
// Consts
    const map<string, string> query_map = map_list_of<string, string>
    ("4556_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 4556")
    ("7552_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 7552")
    ("234x_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 2344 OR PMU_ID = 2345 OR PMU_ID = 2346 OR PMU_ID = 2347 OR PMU_ID = 2348")
    ("813x_SELECT_FILENAME", "SELECT FILENAME FROM Files WHERE PMU_ID = 8132 OR PMU_ID = 8133 OR PMU_ID = 8134 OR PMU_ID = 8135 OR PMU_ID = 8136");
    const map<string, std::vector<int>> vector_map = map_list_of<string, std::vector<int>>
    ("4556", list_of(4556))
    ("7552", list_of(7552))
    ("234x", list_of(2344)(2345)(2346)(2347)(2348))
    ("813x", list_of(8132)(8133)(8134)(8135)(8136));

使用 boost - 可以初始化 const std::containers 以进行测试等。如上面的代码所示，制作 const std::map 或 std::map 非常容易。创建 aconst map<string, std::vector<int>>有点复杂 - 但仍然相当容易。

我试图想出一个const std::map<boost::tuples::tuple<string, string, string>, string>但我无法初始化它。其他人有运气吗？

// Typedefs
typedef boost::tuples::tuple<string, string, string> x3_string_tuple;
// Constants
const map<x3_string_tuple, string> query_selector_map = map_list_of<x3_string_tuple, string>
("4556", "SELECT", "FILENAME"), "4556_SELECT_FILENAME"); // ETC.
4

2 回答 2

22

我试过这个，但它失败了，因为地图的键需要可比较（使用std::less，因此需要operator<定义）。boost::tuple的比较运算符在标题中定义boost/tuple/tuple_comparison.hpp。

包括在内，这段代码工作正常：

#include <boost/assign/list_of.hpp>
#include <boost/tuple/tuple.hpp>
#include <boost/tuple/tuple_comparison.hpp>
#include <map>
#include <string>

using std::string;
typedef boost::tuple<string, string, string> tpl_t;

int main() {
    using boost::assign::map_list_of;
    std::map<tpl_t, string> const m = 
        map_list_of(tpl_t("a","b","c"), "c")(tpl_t("x","y","c"), "z");
}
于 2009-07-07T22:17:07.730 回答
0

我会尝试

const map<x3_string_tuple, string> query_selector_map = map_list_of<x3_string_tuple, string>
(x3_string_tuple("4556", "SELECT", "FILENAME"), "4556_SELECT_FILENAME");

但是，老实说，也许只有 3 个单独的字符串列表更容易，然后将它们一个接一个地组合成一个元组并将其添加到映射中。

于 2009-07-07T21:29:35.707 回答