我听说,sleep() 将锁定当前同步方法/块但是在这里,当我在线程 1 上调用 sleep() 时,线程 2 能够访问同一个块?谁能解释一下?
主.java
public class Main {
public static void main(String args[])
{
Thread1 t1 = new Thread1();
Thread2 t2 = new Thread2();
System.out.println("going to start t1");
t1.start();
System.out.println("going to start t2");
t2.start();
}
}
==================================================== ====================
Thread1.java
public class Thread1 extends Thread{
public void run() {
Syncc s1 = new Syncc();
s1.me("T1:");
}
}
==================================================== ====================
线程2.java
public class Thread2 extends Thread{
public void run() {
Syncc s2 = new Syncc();
s2.me("T2:");
}
}
==================================================== ====================
同步.java
public class Syncc{
public void me(String s){
synchronized(this){
for(int i=0; i<=5; i++)
{
System.out.println(s+" "+" "+i);
try {
Thread.sleep(10000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
===========================================
输出:
going to start t1
going to start t2
T2: 0
T1: 0
T2: 1
T1: 1
T1: 2
T2: 2
T1: 3
T2: 3
T1: 4
T2: 4
T2: 5
T1: 5
但是根据 sleep() 方法,它不应该解锁当前同步块吗?如果是这样,输出应该是..
开始t1 开始t2
T1: 0
T1: 1
T1: 2
T1: 3
T1: 4
T1: 5
T2: 0
T2: 1
T2: 2
T2: 3
T2: 4
T2: 5
我的意思是在线程 1 执行之后,只有线程 2 应该启动对吗?什么问题?