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嗨朋友我正在创建一个 php 页面来将数据从 csv 文件导入到 sql 数据库中。

这里数据库表和字段数由用户自己指定..

如果用户指定 4 个字段，则使用 for 循环创建它，如下所示。

<?php
include('connect.php');
$name = $_POST['table_name'];
//echo $name;

$create_tab = "CREATE TABLE $name(id varchar(15) PRIMARY KEY)";




if(mysql_query($create_tab,$con))
            {
                echo "Table <b><i>$name</i></b> created successfully... <br/> <br/>Add columns...";
            }
            else {
                die('Error1'.mysql_error());
            }



$field = $_POST['number_of_fields'];
//echo $name.$field;
echo '<form id="form1" name="form1" method="post" action="update-table.php">';
echo "<p>
          <label for='tablename'></label>
          <input type='hidden' name='tablename' id='tablename' value='$name' size='5'/>
        </p>";

echo "<p>
          <label for='fields'></label>
          <input type='hidden' name='fields' id='fields' value='$field' size='5'/>
        </p>";
echo '<table border="1" cellpadding="5" cellspacing="5">';
for ( $i = 1; $i <= $field; $i ++) {
    echo '<tr>';
    echo '<td>';
    echo "<p>
          $i
        </p>";
        echo'</td>';

    echo '<td>';
    echo "<p>
          <label for='textfield$i'></label>
          <input type='text' name='field$i' id='textfield$i' />
        </p>";
        echo'</td>';
            echo '<td>';
            echo "
            <select name='select$i' id='select$i'>
                    <option value='varchar(200)'>varchar</option>
                    <option value='int'>int</option>
                    <option value='float'>float</option>
                                        <option value='date'>date</option>
                  </select>";
                echo '</td>';
                                echo '</tr>';


    }
            echo '</table>';
?>
        <p>File Location :
          <input type="text" name="fileField" id="fileField" />
      </p>
<br/>
<INPUT type="image" name="search" src="images/alter.gif" border="0" height="75" width=120">

</form>

然后表创建和更改如下..

 <?php
    include('connect.php');
$field = $_POST[fields]; 
$name = $_POST[tablename];    

for ( $i = 1; $i <= $field; $i++) {
//getting field names
  $varname = ($txtfield . $i);
    $$varname = $_POST[field.$i]; 
  // echo $$varname;
   $fi = $$varname;

//getting field types
  $selname = ($selfield . $i);
    $$selname = $_POST[select.$i]; 
     $dt = $$varname;

$sql = "ALTER TABLE $name ADD $fi $dt";

if(mysql_query($sql,$con))
            {
                echo "Field <b><i>$fi</i></b> added successfully...<br/>";
            }
            else {
                die('Error1'.mysql_error());
            }

    }


?>

如上数据库表和字段被装箱...

我得到了使用静态变量插入数据的概念，如下所示..

<?php
// data import
include('connect.php');


$field = $_POST['fileField']; //file directory

echo "<br/><br/>Import file path: ";
echo $field;

 $file = $field; 

$lines = file($file);
$firstLine = $lines[0];

foreach ($lines as $line_num => $line) {
    if($line_num==0) { continue; } //escape the header column
    $arr = explode(",",$line);
    $column1= $arr[0];
    $column2= $arr[1];
// ' escape character
    if (strpos($column2, "'") == FALSE)
{
    $column21 = $column2;
}
else{
$column21 = str_replace ("'", "\'", $column2);
}
        $column3= $arr[2];
            $column4= $arr[3];

//print data from csv
echo "<table border='1' width='800' cellpadding='5' cellspacing='2'>";
echo "<tr>";
echo "<td width='8'>";
echo $column1;
echo "</td>";
echo "<td width='100'>";
echo $column21;
echo "</td>";
echo "<td width='5'>";
echo $column3;
echo "</td>";
echo "<td width='5'>";
echo $column4;
echo "</td>";
echo "</tr>";
echo "</table>";

     $import="INSERT into $name (id,name,year1,year2) values(

     '$column1','$column21','$column3','$column4')";
     mysql_query($import) or die(mysql_error());

}

?>

现在，我的问题是我怎样才能使这个插入语句动态，因为它从表创建和更改查询中的for循环获得的数据在插入查询中动态创建字段名称和值？

4

2 回答 2

4

如果我正确理解您的问题，听起来您想将插入组合到一个查询中（这在性能方面非常聪明）。SQL 允许您一次插入多行，如下所示：

INSERT INTO table (id, first, last) VALUES(NULL, 'Ryan', 'Silvers'),(NULL, 'Oscar', 'Smith'),(NULL, 'Jessica', 'Owens')

因此，通过创建一个 VALUES 数组并使用 implode 加入它们，您可以进行一个查询：

//Create rows
foreach($rows as $row) {
    $queryRows[] = "(NULL, '".$row['first']."', '".$row['last']."')";
}

//Create query
$query = 'INSERT INTO table (id, first, last) VALUES'.implode(',', $queryRows);

既然我理解了你的真正问题，我可以给你一个基本的概述，说明你需要做些什么来实现这个目标。您需要创建一个表单，允许用户输入将插入到表中的数据。

<form method="post" action="process.php">
    <input name="field1" />
    <!-- and more -->
</form>

然后你需要编写一个PHP脚本来处理表单提交并将数据插入MySQL：

<?php
    //Check form submission and validate entries, then...

    $stmt = $pdo->prepare('INSERT INTO table (field1) VALUES(:field1)');
    $stmt->execute(array(':field1', $_POST['field1']));
?>
于 2012-06-08T07:57:34.090 回答
0

然后你需要编写一个PHP脚本来处理表单提交并将数据插入MySQL：

功能插入（$平板电脑，$datad）{

    if(empty($tablet)) { return false; }

    if(empty($this->CONN)){ return false; }

    $conn = $this->CONN;

    $query1 = "select * from user"; 
    $result1 = mysql_query($query1); 
    $numcolumn = mysql_num_fields($result1); 

    $addd = "";
    $count = 0;
    for ( $i = 1; $i < $numcolumn; $i++ ) 
    { 
        $columnnames = mysql_field_name($result1, $i); 
        if(($numcolumn-1) == $i)
        {
            $addd .= $columnnames;
            $data .= "'".$datad[$count]."'";
        }
        else
        {
            $addd .= $columnnames.",";
            $data .= "'".$datad[$count]."',";
        }
        $count++;
    }
    $ins = "INSERT INTO ".$tablet."(".$addd.")"."VALUES(".$data.")";
    mysql_query($ins);
    header('Location: index.php');
    exit;
}
于 2015-07-15T13:11:19.307 回答