对于作业,我需要将一个对象链表添加到另一个对象的后面。我有这个:
WORD you("you");//where you's linked list now contains y o u
WORD are("are");//where are's linked list now contains a r e
我想这样做:
you.Insert(are,543);//(anything greater they the current objects length is
//attached to the back. So that 543 can be anything > you's length
所以现在,你的链表应该包含:
y o u a r e
我可以在前面插入,也可以在字母之间的任何地方插入,但是当我尝试在后面插入时,程序会立即崩溃。有人可以帮我找出问题所在吗?我尝试使用调试器,它指向一行,但我不知道出了什么问题。我已将该行标记为函数中的传入:
void WORD::Insert(WORD & w, int pos)
{
if(!w.IsEmpty())
{
alpha_numeric *r = w.Cpy();
alpha_numeric *loc;
(*this).Traverse(loc,pos);//pasing Traverse a pointer to a node and the position in the list
//if(loc == 0)
//{
// alpha_numeric *k = r;//k is pointing to the begin. of the copied words list
// while(k -> next != 0)
// {
// k = k -> next;//k goes to the back
// }
// k -> next = front;//k(the back) is now the front of *this
// front = r;//front now points to r, the copy
//}
else if(loc == back)
{
back -> next = r; //<<<-------DEBUGGER SAYS ERROR HERE?
length += w.Length();
while(back -> next!= 0)
{
back = back -> next;
}
}
/*else
{
alpha_numeric *l = r;
while(l -> next != 0)
{
l = l -> next;
}
l -> next = loc -> next;
loc -> next = r;
}
length += w.Length();
}*/
}
另外,如果有帮助,这是我使用的 Traverse 功能
void WORD::Traverse(alpha_numeric * & p, const int & pos)
{
if(pos <= 1)
{
p = 0;
}
else if( pos > (*this).Length())
{
p = back;
}
else
{
p = front;
for(int i = 1; i < pos - 1; i++)
{
p = p -> next;
}
}
}
我在班级的私人部分宣布回来作为指针。*背部
这就是我把它放在构造函数中的方式
WORD::WORD()
{
alpha_numeric *p;
front = new alpha_numeric;
front = 0;
length = 0;
back = front;
for(p = front; p != 0; p = p -> next)
{
back = back -> next;
}
}