javascript - 从 jQuery 或 JS 中的 json 对象中提取数据

Question

我想使用https://raw.github.com/currencybot/open-exchange-rates/master/latest.json提供的货币数据

作为初始测试，我创建了一个精简版作为内联对象：

var obj = [
{
    "disclaimer": "This data is collected from various providers and provided free of charge for informational purposes only, with no guarantee whatsoever of accuracy, validity, availability, or fitness for any purpose; use at your own risk. Other than that, have fun! More info: http://openexchangerates.org/terms/",
    "license": "Data collected from various providers with public-facing APIs; copyright may apply; not for resale; no warranties given. Full license info: http://openexchangerates.org/license/",
    "timestamp": 1339036116,
    "base": "USD",
    "rates": {
        "EUR": 0.795767,
        "GBP": 0.645895,
        "JPY": 79.324997,
        "USD": 1
    }
}];

我想要做的就是以某种方式查询/grep/过滤json对象，例如，“EUR”作为标准，并让它返回一个名为“rate”的变量，结果为“0.795767”。

我查看了 JQuery grep 和 filter 函数，但我不知道如何仅隔离对象的“rates”部分，然后获得我想要的速率。

Answer 1

var obj = [
{
    "disclaimer": "This data is collected from various providers and provided free of charge for informational purposes only, with no guarantee whatsoever of accuracy, validity, availability, or fitness for any purpose; use at your own risk. Other than that, have fun! More info: http://openexchangerates.org/terms/",
    "license": "Data collected from various providers with public-facing APIs; copyright may apply; not for resale; no warranties given. Full license info: http://openexchangerates.org/license/",
    "timestamp": 1339036116,
    "base": "USD",
    "rates": {
        "EUR": 0.795767,
        "GBP": 0.645895,
        "JPY": 79.324997,
        "USD": 1
    }
}];

obj[0].rates.EUR; // output: 0.795767

或者

obj[0].rates['EUR']; output: //0.795767

演示

如果您想在另一个变量中隔离费率并使用该变量，请尝试如下操作：

var rates = obj[0].rates;

现在，

rates.EUR;
rates.GBP;

等等。

Answer 2

您还可以使用JSON.parse()Javascript 的功能将 JSON 字符串转换为 Javascript JSON 对象。

var JSONObject = JSON.parse("{'value1' : 1, 'value2' : 2}");
console.log(JSONObject.value1);  // Prints '1'..

Answer 3

数据包含 FRELD6 尝试：

var reldte;
var sdata = JSON.parse(data);
 $(sdata).each(function () {
        reldte = RefineDate(this.FRELD6.toString());
}