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我是 facebook 应用程序开发的新手,我一直在尝试在用户墙上发布一条简单的消息。我设法获得了访问令牌。这是 POST 请求的代码。我正在使用 java servlet

  String data = URLEncoder.encode("access_token", "UTF-8") + "=" + URLEncoder.encode(accessToken, "UTF-8");
data += "&" + URLEncoder.encode("message", "UTF-8") + "=" + URLEncoder.encode("finally", "UTF-8");
out.println("data is\n"+data);
// Send data
String u="https://graph.facebook.com/me/feed";
URL urls = new URL(u);
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(data);
wr.flush();

好吧,这段代码不起作用,我不能在墙上发帖。关于我可能错在哪里的任何建议?

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1 回答 1

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我很确定这是因为你没有指定application/x-www-form-urlencoded内容类型,试试这个:

URLConnection connection = new URL("https://graph.facebook.com/me/feed").openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");

DataOutputStream out = new DataOutputStream(connection.getOutputStream());
out.writeBytes(data);
out.flush();
out.close()

编辑

好的,所以还有两件事可能会导致此问题:

  1. 您还需要指定内容长度。
  2. 您可能需要阅读响应以使其计数..

此代码已经过测试并且可以正常工作:

StringBuffer buffer = new StringBuffer();
buffer.append("access_token").append('=').append(ACCESS_TOKEN);
buffer.append('&').append("message=").append('=').append("YO!");
String content = buffer.toString();

URLConnection connection = new URL("https://graph.facebook.com/me/feed").openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length", Integer.toString(content.length()));

DataOutputStream out = new DataOutputStream(connection.getOutputStream());
out.writeBytes(content);
out.flush();
out.close();

BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) { 
    System.out.println(inputLine);
}

in.close();
于 2012-06-06T12:17:38.143 回答