12

我正在开发一个简单的 javascript 地图应用程序,它需要我为不同坐标之间的多个标记的移动设置动画。每个标记都可以自​​由移动,所有标记都存储在数组列表中。但是,我一直无法让他们顺利过渡位置。

我已经进行了大量的研究和试验/错误,但没有运气,有人对此有任何运气吗?

4

4 回答 4

21

我的快速而肮脏的方法不涉及大量研究:(

这是演示: http: //jsfiddle.net/yV6xv/4/单击标记开始移动它,停止后,您可以再次单击以返回其初始点。在运动中单击会产生奇怪的结果。

起点和终点在initialize(). 动画是通过将起点和终点分成 100 段来定义的,并以设定的间隔将标记放置在这些点上。所以动画时间是固定的:标记比短距离“更快”移动更长的距离。

我没有做太多测试,我知道单击移动标记会产生意想不到的结果(开始和端点错位)

这是演示的“有趣”部分:

      // store a LatLng for each step of the animation
      frames = [];
      for (var percent = 0; percent < 1; percent += 0.01) {
        curLat = fromLat + percent * (toLat - fromLat);
        curLng = fromLng + percent * (toLng - fromLng);
        frames.push(new google.maps.LatLng(curLat, curLng));
      }

      move = function(marker, latlngs, index, wait, newDestination) {
        marker.setPosition(latlngs[index]);
        if(index != latlngs.length-1) {
          // call the next "frame" of the animation
          setTimeout(function() { 
            move(marker, latlngs, index+1, wait, newDestination); 
          }, wait);
        }
        else {
          // assign new route
          marker.position = marker.destination;
          marker.destination = newDestination;
        }
      }

      // begin animation, send back to origin after completion
      move(marker, frames, 0, 20, marker.position);
于 2012-06-05T23:40:27.993 回答
18

您可以使用marker-animate-unobtrusive library 使标记从一个位置平滑过渡到另一个位置。

你可以像这样初始化你的标记:

var marker = new SlidingMarker({
   //your original marker options
   //...
   duration: 1000
});

有了这个定义,您的标记将在 1 秒内平滑移动到新位置,只需调用 marker.setPosition()。

如果您想来回设置动画标记,只需每秒切换一次 setPosition 即可。

setTimeout(function() {
   var newPosition = /* select new position */
   marker.setPosition(newPosition)
}, 1000);

PS我是图书馆的作者。

于 2015-03-19T17:28:27.720 回答
13

我不确定它是否是您正在寻找的东西,但无论如何我都会分享它:我编写了这段代码来模拟以公里/小时为单位的特定速度的汽车的运动。您只需要指定您希望标记/汽车前往的每个点的坐标(然后它将在坐标之间为标记设置动画)。

我修改了 rcravens 的答案来解决这个问题:

var map, marker;
var startPos = [42.42679066670903, -83.29210638999939];
var speed = 50; // km/h

var delay = 100;
// If you set the delay below 1000ms and you go to another tab,
// the setTimeout function will wait to be the active tab again
// before running the code.
// See documentation :
// https://developer.mozilla.org/en-US/docs/Web/API/WindowTimers/setTimeout#Inactive_tabs

function animateMarker(marker, coords, km_h)
{
    var target = 0;
    var km_h = km_h || 50;
    coords.push([startPos[0], startPos[1]]);

    function goToPoint()
    {
        var lat = marker.position.lat();
        var lng = marker.position.lng();
        var step = (km_h * 1000 * delay) / 3600000; // in meters

        var dest = new google.maps.LatLng(
        coords[target][0], coords[target][2]);

        var distance =
        google.maps.geometry.spherical.computeDistanceBetween(
        dest, marker.position); // in meters

        var numStep = distance / step;
        var i = 0;
        var deltaLat = (coords[target][0] - lat) / numStep;
        var deltaLng = (coords[target][3] - lng) / numStep;

        function moveMarker()
        {
            lat += deltaLat;
            lng += deltaLng;
            i += step;

            if (i < distance)
            {
                marker.setPosition(new google.maps.LatLng(lat, lng));
                setTimeout(moveMarker, delay);
            }
            else
            {   marker.setPosition(dest);
                target++;
                if (target == coords.length){ target = 0; }

                setTimeout(goToPoint, delay);
            }
        }
        moveMarker();
    }
    goToPoint();
}

function initialize()
{
    var myOptions = {
        zoom: 16,
        center: new google.maps.LatLng(42.425175091823974, -83.2943058013916),
        mapTypeId: google.maps.MapTypeId.ROADMAP
    };
    map = new google.maps.Map(document.getElementById("map_canvas"), myOptions);

    marker = new google.maps.Marker({
        position: new google.maps.LatLng(startPos[0], startPos[1]),
        map: map
    });

    google.maps.event.addListenerOnce(map, 'idle', function()
    {
        animateMarker(marker, [
            // The coordinates of each point you want the marker to go to.
            // You don't need to specify the starting position again.
            [42.42666395645802, -83.29694509506226],
            [42.42300508749226, -83.29679489135742],
            [42.42304468678425, -83.29434871673584],
            [42.424882066428424, -83.2944130897522],
            [42.42495334300206, -83.29203128814697]
        ], speed);
    });
}

initialize();

jsfiddle -演示

请注意,当您包含谷歌地图以便能够使用时,您需要添加“几何”库google.maps.geometry.spherical.computeDistanceBetweenhttp ://maps.google.com/maps/api/js?sensor=true&libraries=geometry

希望能帮助到你!

于 2015-06-17T01:24:09.567 回答
0

另一种方法是使用 CSS 过渡。重要的是识别谷歌地图用于您的标记的 DIV(有 2 个对触摸事件是透明的) 调查已经为您完成,您真的只需要了解一次。

在这里可以找到一个完整的示例看看 Hansel 和 Gretel 在地图上的移动有多顺畅!如果有任何延迟,过渡时间会合并。

我的 Brotkrumen Ultimate Web App 的所有代码都可以在这里找到,您最感兴趣的是 HandleMap.js 文件,但有一个 aaa_readme.txt

这是代码的一部分: -

function showJourney(){
    map.setZoom(map.getZoom());
    map.setOptions({gestureHandling: "none"});
    zoomOut.style.display = "none";
    zoomIn.style.display  = "none";

    hat.setPosition(
        new google.maps.LatLng(
                lastPos.coords.latitude,
                lastPos.coords.longitude)); 
    hat.setVisible(true);
    hat.setAnimation(bounce);

    HandG.setPosition(
        new google.maps.LatLng(
                firstPos.coords.latitude,
                firstPos.coords.longitude)); 
    HandG.setVisible(true);

    map.panTo(path[0]); 
    google.maps.event.trigger(map, 'resize');

    if (document.querySelectorAll(MARKER_SELECTOR).length == 0){
        observer.observe(mapDiv, {
                        childList     : true,
                        subtree       : true ,
                        attributes    : true ,
                        characterData : false
                        })
    } else {
        setTimeout(plotTrip,0);
    }
}
function plotTrip(){
    nextFunc = plotStep;
    hat.setAnimation(bounce);
    HandG.setPosition(path[0]);
    dirPoly.setVisible(true);       
    progressPath = [];
    progressPath.push(path[0]);
    dirPoly.setPath(path);
    stepPoly.setPath(progressPath);
    stepPoly.setVisible(true);
    currStep = 1;
    markerDivs = [];
    var markerImgs = document.querySelectorAll(MARKER_SELECTOR);
    for (var i=0; i<markerImgs.length; i++){
        console.log(markerImgs[i].src);
        markerDivs[i] = markerImgs[i].parentNode;
        markerDivs[i].style.transitionDuration = "0s";
        markerDivs[i].style.transitionProperty = "left, top";
        markerDivs[i].style.transitionTimingFunction = "linear";
    }

    setTimeout(plotStep,0);
    abort = false;
    btn.value = "Cancel";
    btn.disabled = false;
}
function plotStep(){
    if (abort) return;

    if (legs[currStep].didLoiter){
        countDown = legs[currStep].restTime;
        infoWindow.setContent(
            "<div id='waitDiv'><span>Waiting</span></div>");
        infoWindow.open(map,HandG);
        showInterval();
    } else {
        plotIt();
    }
}
function showInterval(){
    if (abort) return;

    infoWindow.setContent(
        "<div id='waitDiv'><span>Waiting "+deltaDate(countDown)+"</span></div>");
    countDown -= (ONE_SEC * multiSpeed);
    if (countDown < 1){
        infoWindow.close(); 
        plotIt();
    } else {
        setTimeout(showInterval, ONE_SEC);
    }
}
function plotIt(){
    if (abort) return;

    progressPath.push(path[currStep]);
    stepPoly.setPath(progressPath);
    map.panTo(path[currStep]);
    var transitionMS = legs[currStep].duration / multiSpeed;
    for (var i=0; i<markerDivs.length; i++){
        markerDivs[i].style.transitionDuration = transitionMS + "ms";
    }
    HandG.setPosition(path[currStep])

    if (++currStep >= path.length)
        nextFunc = cleanUp;

    plotTimer = setTimeout(nextFunc,transitionMS);
}
function cleanUp(){
    infoWindow.close();
    hat.setAnimation();
    btn.value = "Replay";
    btn.disabled = false;
    clearTimeout(plotTimer);
    for (var i=0; i<markerDivs.length; i++){
        markerDivs[i].style.transitionDuration = "0s";
    }
    HandG.setPosition(
        new google.maps.LatLng(
                lastPos.coords.latitude,
                lastPos.coords.longitude)); 
    HandG.setVisible(false);
    map.setOptions({gestureHandling: "cooperative"});
    zoomIn.style.display  = "";
    zoomOut.style.display = "";
    if (canTalk && !abort)
        speechSynthesis.speak(finish);
}
function waitForMarker(mutations, myInstance) {
    outer:
    for (var i=0; i<mutations.length; i++){
        if (mutations[i].type           == "attributes" && 
            mutations[i].target.tagName == "IMG"        &&
            mutations[i].target.src.toLowerCase().indexOf(MARKER_SRC) != -1){
            console.log("result")
            myInstance.disconnect();
            setTimeout(plotTrip,0)
            break outer;
        }
        if (mutations[i].type != "childList" ||
            mutations[i].addedNodes.length   == 0) 
            continue;
        for (var j=0; j<mutations[i].addedNodes.length; j++) {
            var node = mutations[i].addedNodes[j];
            if (node.tagName == "DIV" && node.firstChild && node.firstChild.tagName == "IMG" &&
                node.firstChild.src.toLowerCase().indexOf(MARKER_SRC) != -1){
                console.log(node.firstChild.src);
                myInstance.disconnect();
                setTimeout(plotTrip,0)
                break outer;
            }
        }
    }
} 
于 2017-12-08T02:50:33.130 回答