python - 当 sweetpie 连接非 ORM 源​​时，如何返回 404？

Question

我正在使用此处描述的类似外观的模式：http: //django-tastypie.readthedocs.org/en/latest/non_orm_data_sources.html

def obj_get(self, request=None, **kwargs):
    rv = MyObject(init=kwargs['pk'])
    audit_trail.message( ... )
    return rv

我不能返回 None，抛出一个错误。

Answer 1

您应该提出一个异常：tastepie.exceptions.NotFound（根据代码文档）。

我正在为 CouchDB 开发美味的派，并深入研究了这个问题。在 sweetpie.resources.Resource 类中，您可以找到必须覆盖的方法：

def obj_get(self, request=None, **kwargs):
    """
    Fetches an individual object on the resource.

    This needs to be implemented at the user level. If the object can not
    be found, this should raise a ``NotFound`` exception.

    ``ModelResource`` includes a full working version specific to Django's
    ``Models``.
    """
    raise NotImplementedError()

我的例子：

def obj_get(self, request=None, **kwargs):
    """
    Fetches an individual object on the resource.

    This needs to be implemented at the user level. If the object can not
    be found, this should raise a ``NotFound`` exception.
    """
    id_ = kwargs['pk']
    ups = UpsDAO().get_ups(ups_id = id_)
    if ups is None:
        raise NotFound(
                "Couldn't find an instance of '%s' which matched id='%s'."%
                ("UpsResource", id_))
    return ups

有一件事对我来说很奇怪。当我查看 ModelResource 类（Resource 类的超类）中的 obj_get 方法时：

def obj_get(self, request=None, **kwargs):
    """
    A ORM-specific implementation of ``obj_get``.

    Takes optional ``kwargs``, which are used to narrow the query to find
    the instance.
    """
    try:
        base_object_list = self.get_object_list(request).filter(**kwargs)
        object_list = self.apply_authorization_limits(request, base_object_list)
        stringified_kwargs = ', '.join(["%s=%s" % (k, v) for k, v in kwargs.items()])

        if len(object_list) <= 0:
            raise self._meta.object_class.DoesNotExist("Couldn't find an instance of '%s' which matched '%s'." % (self._meta.object_class.__name__, stringified_kwargs))
        elif len(object_list) > 1:
            raise MultipleObjectsReturned("More than '%s' matched '%s'." % (self._meta.object_class.__name__, stringified_kwargs))

        return object_list[0]
    except ValueError:
        raise NotFound("Invalid resource lookup data provided (mismatched type).")

一个异常：self._meta.object_class.DoesNotExist 在找不到对象时引发，最终成为 ObjectDoesNotExist 异常-因此在项目内部没有达成共识。

Answer 2

我使用来自 django.core.exceptions 的 ObjectDoesNotExist exeption

   def obj_get(self, request=None, **kwargs):
        try:
            info = Info.get(kwargs['pk'])
        except ResourceNotFound:
            raise ObjectDoesNotExist('Sorry, no results on that page.')
        return info