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我有一个 XPath,它可以获取我想要阅读的 div。如何使用一个 XPath 读取 div 的类和名称?

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2 回答 2

1
<?php 
        $xmlDoc = new DOMDocument(); 
        $xmlDoc->load( '<<your file>>>' ); 
    //$xmlDoc->loadHTML($sourceString); //-> if its a string you have
        $xpath = new DOMXpath($doc);
        $elements = $xpath->query("Your XPath");

        //if you are sure there is only one div, for the Xpath, you can use a index 0 in the next statement, else uou have to itereate it in a loop

    $node = $elements->item(0);

    $attrib1 = $node->attributes->getNamedItem("<attribute_name1>");
    $attrib2 = $node->attributes->getNamedItem("<attribute_name2>");
    $attrib3 = $node->attributes->getNamedItem("<attribute_name3>");
    ....



        ?> 
于 2012-06-05T13:47:09.507 回答
0

此代码选择具有属性名称和类的所有 div。请参阅下文以了解如何从所选节点中选择信息。

<?php

    $xmlstring = '<root>' .
        '<div name="value1" class="value2" myarg="value3"></div>' .
        '<div name="value4"></div>' .
    '</root>';
    $xml = simplexml_load_string($xmlstring);

    // Select all div's that have attributes name and class
    $xpath = "//div[@name and @class]"; 
    var_dump($result = $xml->xpath($xpath));

    /* Outputs:
        array(1) {
          [0]=>
          object(SimpleXMLElement)#3 (1) {
            ["@attributes"]=>
            array(3) {
              ["name"]=>
              string(6) "value1"
              ["class"]=>
              string(6) "value2"
              ["myarg"]=>
              string(6) "value3"
            }
          }
        }   
    */

    // note that only one iteration is performed
    // as the second div does not have an attribut
    // called 'class'.
    foreach($result as $element)
    {
        echo $element['name'];   // value1
        echo $element['class'];  // value2
    } 

    // or, if only one div is present in the document:
    echo $result[0]['name'];     // value1
    echo $result[0]['class'];    // value2  

?>
于 2012-06-05T18:46:02.683 回答