我尝试通过 jdbcTemplate 对 MySql 数据库执行简单请求，但是当框架加载和解析定义我的数据源的 xml 文件时出现错误：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd">
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://localhost:3306/spring_training"/>
<property name="username" value="root"/>
<property name="password" value="pass"/>
</bean>
</beans>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>SpringTrainingTemplate</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-config.xml /WEB-INF/jdbc-config.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>hello</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>hello</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
和调用它的控制器：
@Controller
public class HomeController {
@Autowired
private ExampleService exampleService;
@RequestMapping(value = "/details", method = RequestMethod.GET)
public String details(Model model) {
ApplicationContext context = new ClassPathXmlApplicationContext("jdbc-config.xml");
ExampleDao dao = (ExampleDao) context.getBean("ExampleDao");
List<Application> list = dao.getAllApplications();
model.addAttribute("application", list.get(0).getName());
model.addAttribute("descriptionOfApplication", list.get(0).getDescription());
return "details";
}
}
public class ExampleDao {
private String request = "select * from application";
private JdbcTemplate jdbcTemplate;
@Autowired
private DataSource dataSource;
public ExampleDao(DataSource dataSource) {
this.jdbcTemplate = new JdbcTemplate(dataSource);
}
public List<Application> getAllApplications() {
List<Application> applications = this.jdbcTemplate.query(request, new RowMapper<Application>() {
@Override
public Application mapRow(ResultSet rs, int i) throws SQLException {
Application application = new Application();
application.setName(rs.getString("name"));
application.setType(rs.getString("type"));
application.setDescription(rs.getString("description"));
application.setDownloads(rs.getInt("downloads"));
return application;
}
});
return applications;
}
}
当我运行它并输入时，http://localhost:8080/details我得到了一个带有堆栈跟踪的 500 异常，并带有以下消息：
root cause
org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [jdbc-config.xml]; nested exception is java.io.FileNotFoundException: class path resource [jdbc-config.xml] cannot be opened because it does not exist
你能解释一下如何以正确的方式配置 jdbc 连接，或者我的方法是否正确，我应该在哪里寻找我的问题的解决方案？所有帮助将不胜感激。谢谢。