python - How can I memoize a class instantiation in Python?

Question

Ok, here is the real world scenario: I'm writing an application, and I have a class that represents a certain type of files (in my case this is photographs but that detail is irrelevant to the problem). Each instance of the Photograph class should be unique to the photo's filename.

The problem is, when a user tells my application to load a file, I need to be able to identify when files are already loaded, and use the existing instance for that filename, rather than create duplicate instances on the same filename.

To me this seems like a good situation to use memoization, and there's a lot of examples of that out there, but in this case I'm not just memoizing an ordinary function, I need to be memoizing __init__(). This poses a problem, because by the time __init__() gets called it's already too late as there's a new instance created already.

In my research I found Python's __new__() method, and I was actually able to write a working trivial example, but it fell apart when I tried to use it on my real-world objects, and I'm not sure why (the only thing I can think of is that my real world objects were subclasses of other objects that I can't really control, and so there were some incompatibilities with this approach). This is what I had:

class Flub(object):
    instances = {}

    def __new__(cls, flubid):
        try:
            self = Flub.instances[flubid]
        except KeyError:
            self = Flub.instances[flubid] = super(Flub, cls).__new__(cls)
            print 'making a new one!'
            self.flubid = flubid
        print id(self)
        return self

    @staticmethod
    def destroy_all():
        for flub in Flub.instances.values():
            print 'killing', flub


a = Flub('foo')
b = Flub('foo')
c = Flub('bar')

print a
print b
print c
print a is b, b is c

Flub.destroy_all()

Which output this:

making a new one!
139958663753808
139958663753808
making a new one!
139958663753872
<__main__.Flub object at 0x7f4aaa6fb050>
<__main__.Flub object at 0x7f4aaa6fb050>
<__main__.Flub object at 0x7f4aaa6fb090>
True False
killing <__main__.Flub object at 0x7f4aaa6fb050>
killing <__main__.Flub object at 0x7f4aaa6fb090>

It's perfect! Only two instances were made for the two unique id's given, and Flub.instances clearly only has two listed.

But when I tried to take this approach with the objects I was using, I got all kinds of nonsensical errors about how __init__() took only 0 arguments, not 2. So I'd change some things around and then it would tell me that __init__() needed an argument. Totally bizarre.

After a while of fighting with it, I basically just gave up and moved all the __new__() black magic into a staticmethod called get, such that I could call Photograph.get(filename) and it would only call Photograph(filename) if filename wasn't already in Photograph.instances.

Does anybody know where I went wrong here? Is there some better way to do this?

Another way of thinking about it is that it's similar to a singleton, except it's not globally singleton, just singleton-per-filename.

Here's my real-world code using the staticmethod get if you want to see it all together.

score 20 · Accepted Answer

Let us see two points about your question.

Using memoize

You can use memoization, but you should decorate the class, not the __init__ method. Suppose we have this memoizator:

def get_id_tuple(f, args, kwargs, mark=object()):
    """ 
    Some quick'n'dirty way to generate a unique key for an specific call.
    """
    l = [id(f)]
    for arg in args:
        l.append(id(arg))
    l.append(id(mark))
    for k, v in kwargs:
        l.append(k)
        l.append(id(v))
    return tuple(l)

_memoized = {}
def memoize(f):
    """ 
    Some basic memoizer
    """
    def memoized(*args, **kwargs):
        key = get_id_tuple(f, args, kwargs)
        if key not in _memoized:
            _memoized[key] = f(*args, **kwargs)
        return _memoized[key]
    return memoized

Now you just need to decorate the class:

@memoize
class Test(object):
    def __init__(self, somevalue):
        self.somevalue = somevalue

Let us see a test?

tests = [Test(1), Test(2), Test(3), Test(2), Test(4)]
for test in tests:
    print test.somevalue, id(test)

The output is below. Note that the same parameters yield the same id of the returned object:

1 3072319660
2 3072319692
3 3072319724
2 3072319692
4 3072319756

Anyway, I would prefer to create a function to generate the objects and memoize it. Seems cleaner to me, but it may be some irrelevant pet peeve:

class Test(object):
    def __init__(self, somevalue):
        self.somevalue = somevalue

@memoize
def get_test_from_value(somevalue):
    return Test(somevalue)

Using `new`:

Or, of course, you can override __new__. Some days ago I posted an answer about the ins, outs and best practices of overriding __new__ that can be helpful. Basically, it says to always pass *args, **kwargs to your __new__ method.

I, for one, would prefer to memoize a function which creates the objects, or even write a specific function which would take care of never recreating a object to the same parameter. Of course, however, this is mostly a opinion of mine, not a rule.

score 8 · Accepted Answer

The solution that I ended up using is this:

class memoize(object):
    def __init__(self, cls):
        self.cls = cls
        self.__dict__.update(cls.__dict__)

        # This bit allows staticmethods to work as you would expect.
        for attr, val in cls.__dict__.items():
            if type(val) is staticmethod:
                self.__dict__[attr] = val.__func__

    def __call__(self, *args):
        key = '//'.join(map(str, args))
        if key not in self.cls.instances:
            self.cls.instances[key] = self.cls(*args)
        return self.cls.instances[key]

And then you decorate the class with this, not __init__. Although brandizzi provided me with that key piece of information, his example decorator didn't function as desired.

I found this concept quite subtle, but basically when you're using decorators in Python, you need to understand that the thing that gets decorated (whether it's a method or a class) is actually replaced by the decorator itself. So for example when I'd try to access Photograph.instances or Camera.generate_id() (a staticmethod), I couldn't actually access them because Photograph doesn't actually refer to the original Photograph class, it refers to the memoized function (from brandizzi's example).

To get around this, I had to create a decorator class that actually took all the attributes and static methods from the decorated class and exposed them as it's own. Almost like a subclass, except that the decorator class doesn't know ahead of time what classes it will be decorating, so it has to copy the attributes over after the fact.

The end result is that any instance of the memoize class becomes an almost transparent wrapper around the actual class that it has decorated, with the exception that attempting to instantiate it (but really calling it) will provide you with cached copies when they're available.

score 2 · Accepted Answer

The parameters to __new__ also get passed to __init__, so:

def __init__(self, flubid):
    ...

You need to accept the flubid argument there, even if you don't use it in __init__

Here is the relevant comment taken from typeobject.c in Python2.7.3

/* You may wonder why object.__new__() only complains about arguments
   when object.__init__() is not overridden, and vice versa.

   Consider the use cases:

   1. When neither is overridden, we want to hear complaints about
      excess (i.e., any) arguments, since their presence could
      indicate there's a bug.

   2. When defining an Immutable type, we are likely to override only
      __new__(), since __init__() is called too late to initialize an
      Immutable object.  Since __new__() defines the signature for the
      type, it would be a pain to have to override __init__() just to
      stop it from complaining about excess arguments.

   3. When defining a Mutable type, we are likely to override only
      __init__().  So here the converse reasoning applies: we don't
      want to have to override __new__() just to stop it from
      complaining.

   4. When __init__() is overridden, and the subclass __init__() calls
      object.__init__(), the latter should complain about excess
      arguments; ditto for __new__().

   Use cases 2 and 3 make it unattractive to unconditionally check for
   excess arguments.  The best solution that addresses all four use
   cases is as follows: __init__() complains about excess arguments
   unless __new__() is overridden and __init__() is not overridden
   (IOW, if __init__() is overridden or __new__() is not overridden);
   symmetrically, __new__() complains about excess arguments unless
   __init__() is overridden and __new__() is not overridden
   (IOW, if __new__() is overridden or __init__() is not overridden).

   However, for backwards compatibility, this breaks too much code.
   Therefore, in 2.6, we'll *warn* about excess arguments when both
   methods are overridden; for all other cases we'll use the above
   rules.

*/

python - How can I memoize a class instantiation in Python?

3 回答 3

Using memoize

Using __new__:

Related

Reference

Using `new`: