13

我正在尝试通过interviewstreet学习 erlang 。我现在只是学习语言,所以我几乎一无所知。我想知道如何从标准输入读取并写入标准输出。

我想写一个简单的程序来写“Hello World!” 在标准输入中接收的次数。

所以使用标准输入:

6

写入标准输出:

Hello World!
Hello World!
Hello World!
Hello World!
Hello World!
Hello World!

理想情况下,我将一次读取一行标准输入(即使在这种情况下它只是一位数字),所以我想我将使用 get_line。这就是我现在所知道的。

谢谢

谢谢

4

3 回答 3

24

这是另一种解决方案,可能更实用。

#!/usr/bin/env escript

main(_) ->
    %% Directly reads the number of hellos as a decimal
    {ok, [X]} = io:fread("How many Hellos?> ", "~d"),
    %% Write X hellos
    hello(X).

%% Do nothing when there is no hello to write
hello(N) when N =< 0 -> ok;
%% Else, write a 'Hello World!', and then write (n-1) hellos
hello(N) ->
   io:fwrite("Hello World!~n"),
   hello(N - 1).
于 2012-06-03T19:30:31.273 回答
1

这是我的镜头。我使用了 escript 所以它可以从命令行运行,但它可以很容易地放入一个模块中:

#!/usr/bin/env escript

main(_Args) ->
    % Read a line from stdin, strip dos&unix newlines
    % This can also be done with io:get_line/2 using the atom 'standard_io' as the
    % first argument.
    Line = io:get_line("Enter num:"), 
    LineWithoutNL = string:strip(string:strip(Line, both, 13), both, 10),

    % Try to transform the string read into an unsigned int
    {ok, [Num], _} = io_lib:fread("~u", LineWithoutNL),

    % Using a list comprehension we can print the string for each one of the
    % elements generated in a sequence, that goes from 1 to Num.
    [ io:format("Hello world!~n") || _ <- lists:seq(1, Num) ].

如果您不想使用列表推导,这是与最后一行代码类似的方法,使用 lists:foreach 和相同的序列:

    % Create a sequence, from 1 to Num, and call a fun to write to stdout
    % for each one of the items in the sequence.
    lists:foreach(
        fun(_Iteration) ->
            io:format("Hello world!~n")
        end,
        lists:seq(1,Num)
    ).
于 2012-06-03T19:18:30.470 回答
0
% Enter your code here. Read input from STDIN. Print output to STDOUT 
% Your class should be named solution

-module(solution).
-export([main/0, input/0, print_hello/1]).

main() ->
    print_hello(input()).

print_hello(0) ->io:format("");
print_hello(N) ->
    io:format("Hello World~n"),
    print_hello(N-1).
input()->
    {ok,[N]} = io:fread("","~d"),
N.
于 2017-04-04T18:48:31.397 回答