1

嗨，每当我们使用 bussoc paypal 快速结帐选项时.. 输入 paypal 帐户登录和付款继续按钮后，会出现一条带有 mysql 服务器错误的消息，即使客户在 paypal 付款后回来时也会出现此消息

注意：错误，您的 SQL 语法有错误，请检查与您的 MYSQL 服务器版本相对应的手册，以获取正确的语法，以便在第 1 行的订单附近使用 SET customer_id='27' WHERE order_id='279'

错误号 1064

UPDATE order SET customer_id='27'WHERE order_id='279' in home/public_html/site/system/database/mysql.php line 49 这是查询。那么它需要改变的地方呢？

<?php
final class MySQL {
private $connection;

public function __construct($hostname, $username, $password, $database) {
    if (!$this->connection = mysql_connect($hostname, $username, $password)) {
        exit('Error: Could not make a database connection using ' . $username . '@' . $hostname);
    }

    if (!mysql_select_db($database, $this->connection)) {
        exit('Error: Could not connect to database ' . $database);
    }
    
    mysql_query("SET NAMES 'utf8'", $this->connection);
    mysql_query("SET CHARACTER SET utf8", $this->connection);
    mysql_query("SET CHARACTER_SET_CONNECTION=utf8", $this->connection);
    mysql_query("SET SQL_MODE = ''", $this->connection);
}
    
public function query($sql) {
    $resource = mysql_query($sql, $this->connection);

    if ($resource) {
        if (is_resource($resource)) {
            $i = 0;
    
            $data = array();
    
            while ($result = mysql_fetch_assoc($resource)) {
                $data[$i] = $result;
    
                $i++;
            }
            
            mysql_free_result($resource);
            
            $query = new stdClass();
            $query->row = isset($data[0]) ? $data[0] : array();
            $query->rows = $data;
            $query->num_rows = $i;
            
            unset($data);

            return $query;  
        } else {
            return true;
        }
    } else {
        trigger_error('Error: ' . mysql_error($this->connection) . '<br />Error No: ' . mysql_errno($this->connection) . '<br />' . $sql);
        exit();
    }
}

public function escape($value) {
    return mysql_real_escape_string($value, $this->connection);
}

public function countAffected() {
    return mysql_affected_rows($this->connection);
}

public function getLastId() {
    return mysql_insert_id($this->connection);
}   

public function __destruct() {
    mysql_close($this->connection);
}
}
?>
4

2 回答 2

1 
update `oc_order` 
SET customer_id='27' 
WHERE order_id='279'

你已经为表名添加了前缀。这个前缀是在你安装 opencart 时添加的。

默认情况下它是'oc_'，如果你改变它然后用那个替换它

于 2015-04-17T06:18:53.153 回答
1

您的表名是order。那是 MySQL 中的保留关键字。你需要用反引号来逃避它

update `order` 
SET customer_id='27' 
WHERE order_id='279'
于 2012-06-03T15:30:44.260 回答