我很高兴收到关于我的另一个问题的以下日期排序代码:) 但我有一个快速查询。
如何按从 min-date 到 max-date 的顺序显示 min-date 和 max-date 的结果?
jQuery:
$(function() {
$.datepicker.setDefaults({ dateFormat: "dd/mm/yy" }); //sets default datepicker's dateFormat
$("#mindate, #maxdate")
.datepicker() //initializes both of the date inputs as jQuery UI datepickers
.on('keypress keyup change blur', function(){ filter(); }); //sets listeners to filter the table on the fly
});
function filter(){
$('tr').show(); //resets table to default before executing the filter
datefields = $('table.bordered tr td:nth-child(2)'); //stores a jquery oject containing all tds of the 2nd column (dates)
datefields.each(function(){ //iterates through them..
var evdate = pdate($(this).html()); //evaluates each of their dates as date objects
var mindate = pdate($('#mindate').val()); //evaluates the entered mindate (will return false if not valid*)
if (mindate) //checks if the mindate is valid
if (evdate < mindate)
$(this).parent().hide(); //hides the row if its date is previous to the mindate
var maxdate = pdate($('#maxdate').val()); //repeats same as above, now for maxdate filtering
if (maxdate)
if (evdate > maxdate)
$(this).parent().hide(); //hides the row if its date is after the maxdate
});
}
function pdate(str){ //parse date function, receives a string and returns a date if it's valid or false if it isn't
if (!isValidDate(str))
return false; //returns false if the date isn't valid
var parts = str.split("/");
// new Date(year, month [, date [, hours[, minutes[, seconds[, ms]]]]])
return new Date(parts[2], parts[1]-1, parts[0]);
}
//this is my custom date validating function, much better than those which you may find in the web :P
function isValidDate(date)
{
parts = date.split('/');
if (parts.length != 3)
return false;
else if (parts[0] == '' || /[^0-9]/.test(parts[0]) || parts[1] == '' || /[^0-9]/.test(parts[1]) || parts[2] == '' || /[^0-9]/.test(parts[2]))
return false;
day = parts[0];
month = parts[1];
year = parts[2];
if (year >= 1800 && year <= 2200) //define the limits of valid dates
{
if (day > 0 && day <= 31 && month > 0 && month <= 12)
{
if ((month == 4 || month == 6 || month == 9 || month == 11) && day > 30)
return false;
if (month == 2)
{
if (year%4 == 0 && (year%100 != 0 || year%400==0))
{
if (day > 29)
return false;
}
else if (day > 28)
return false;
}
return true;
}
else
return false;
}
else
return false;
}