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我正在尝试创建一个触发器来使用条件检查更新另一个表,但我不断收到 MySQL 错误。我的触发器的代码是:

DELIMITER $$
CREATEb
TRIGGER visitor_validation
BEFORE INSERT ON ratingsvisitors
FOR EACH ROW
BEGIN
Set @counts=(SELECT count(*) from ratingsvisitors where visotrid=new.userid AND  profileid=New.profileid AND itemid=New.itemid AND likevalidation=New.likevalidation AND likesordislike=New.likesordislike);
SET @ifexists = (SELECT * FROM ratingcounttracks WHERE userid=New.userid AND likedate=New.likevalidation AND countfor=New.likesordislike);
IF (@ifexists = NULL) THEN
INSERT INTO  ratingsvisitors(userid, likedate, clickcount,countfor) values (New.userid, New.likevalidation ,'1',New.likesordislike);
ELSE
UPDATE ratingsvisitors SET clickcount=clickcount+1 WHERE userid=New.userid AND likedate=New.likevalidation AND countfor=New.likesordislike;
ENDIF;
END$$

MySQL显示错误:

#1064 - 您的 SQL 语法有错误;检查与您的 MySQL 服务器版本相对应的手册,以获取在 '; 附近使用的正确语法。END' 在第 12 行

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1 回答 1

3

你可以做这样的事情

DELIMITER $$
CREATE
TRIGGER visitor_validation
BEFORE INSERT ON ratingsvisitors
FOR EACH ROW
BEGIN
Set @counts=(SELECT count(*) from ratingsvisitors where visotrid=new.userid AND     
profileid=New.profileid AND itemid=New.itemid AND likevalidation=New.likevalidation AND  
likesordislike=New.likesordislike);
IF NOT EXISTS (SELECT * FROM ratingcounttracks WHERE userid=New.userid AND   
likedate=New.likevalidation AND countfor=New.likesordislike);
THEN
INSERT INTO  ratingsvisitors(userid, likedate, clickcount,countfor) values (New.userid, 
New.likevalidation ,'1',New.likesordislike);
ELSE
UPDATE ratingsvisitors SET clickcount=clickcount+1 WHERE userid=New.userid AND 
likedate=New.likevalidation AND countfor=New.likesordislike;
ENDIF;
END$$
于 2012-06-21T10:49:44.543 回答