android - 从 android 应用程序调用 Web 服务

Question

我需要从 android 应用程序调用 Web 服务。我有在 java 中创建的 web 服务的 wsdl 文件，我没有相同的源代码。在 java 中，我使用“生成客户端”选项从 wsdl 生成文件，然后使用 Axis.jar 通过我的 java 应用程序调用 Web 服务。当我单击“生成客户端”选项时，会生成文件以及一些编译错误。但是当我在 java 应用程序中做同样的事情时，生成的文件没有任何编译错误。请告知android预期的正确方法。问候，

Answer 1

在 android 中，您可以使用 ksoap 库并调用所需的 web 服务。使用构建路径包含 ksoap 库并使用以下代码调用 Web 服务。在这个路径中找到ksoap库 ksoap库路径

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.MarshalBase64;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;

import android.app.Activity;
import android.os.Bundle;

public class SVCWebServiceActivity extends Activity {
    /** Called when the activity is first created. */
    private static final String SOAP_ACTION = "http://tempuri.org/GetByteArray";
    private static final String METHOD_NAME = "GetByteArray";
    private static final String NAMESPACE = "http://tempuri.org/";
    private static final String URL = "http://IPAddress/Serviceforc/Service.asmx";
    private String byteStr = "srikar";
    private byte[] bytedata = byteStr.getBytes();
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        System.out.println("bytedata is "+bytedata[0]);
        HttpTransportSE httpTransport = null;
        MarshalBase64 marshal = null;
        SoapObject request = null;
        request = new SoapObject(NAMESPACE, METHOD_NAME);
        PropertyInfo pi = new PropertyInfo();       
        pi.setName("value");
        pi.setValue(bytedata);
        pi.setType(MarshalBase64.BYTE_ARRAY_CLASS);
        request.addProperty(pi);
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                SoapEnvelope.VER11);
        envelope.dotNet = true;
        marshal = new MarshalBase64();
        marshal.register(envelope);
        envelope.setOutputSoapObject(request);

        httpTransport = new HttpTransportSE(URL);

        Object response;
        try {
            httpTransport.call(SOAP_ACTION, envelope);
            response = envelope.getResponse();
        } catch (Exception exception) {
            exception.printStackTrace();
            System.out.println("Exception is " + exception.toString());
            // strRes = exception.toString();
            response = exception.toString();

        }
        System.out.println("Response is "+response.toString());
}
}