3

我有三个可以通过硬件自动同步的火线摄像机，我正在尝试捕获帧，将它们保存到我的硬盘中并在窗口中显示它们。

一切正常，但目前，我只能同时在三个不同的窗口中显示框架。

我想在单个窗口中显示框架，但我不知道该怎么做。在此链接上有 cvShowManyImages() 函数，但您必须同时传递三帧，但我有一个 for() 循环，可以一次考虑一帧。

这是我正在使用的代码：

  for ( int j = 0; j < k_numImages; j++ )
    {
        // Display the timestamps for all cameras to show that the image
        // capture is synchronized for each image
        for ( unsigned int i = 0; i < numCameras; i++ )
        {
            Image image;
            error = ppCameras[i]->RetrieveBuffer( &image );
            if (error != PGRERROR_OK)
            {
                PrintError( error );
                return -1;
            }
            IplImage* destImage = ConvertImageToOpenCV(&image);
            char titolo[50];
            sprintf(titolo, "titolo%d", i);
            cvShowImage(titolo, destImage);
            waitKey(1);
        }
   }

它工作得很好，但我想在同一个窗口中显示所有相机帧时为每个相机创建一个不同的窗口。

你能帮我吗？

编辑：这是 ConvertImageToOpenCV() 函数。

IplImage* ConvertImageToOpenCV(Image* pImage)
{
    IplImage* cvImage = NULL;
    bool bColor = true;
    CvSize mySize;
    mySize.height = pImage->GetRows();
    mySize.width = pImage->GetCols();

    switch ( pImage->GetPixelFormat() )
    {
        case PIXEL_FORMAT_MONO8:     cvImage = cvCreateImageHeader(mySize, 8, 1 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 1;
                                     bColor = false;
                                     break;
        case PIXEL_FORMAT_411YUV8:   cvImage = cvCreateImageHeader(mySize, 8, 3 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_422YUV8:   cvImage = cvCreateImageHeader(mySize, 8, 3 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_444YUV8:   cvImage = cvCreateImageHeader(mySize, 8, 3 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_RGB8:      cvImage = cvCreateImageHeader(mySize, 8, 3 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_MONO16:    cvImage = cvCreateImageHeader(mySize, 16, 1 );
                                     cvImage->depth = IPL_DEPTH_16U;
                                     cvImage->nChannels = 1;
                                     bColor = false;
                                     break;
        case PIXEL_FORMAT_RGB16:     cvImage = cvCreateImageHeader(mySize, 16, 3 );
                                     cvImage->depth = IPL_DEPTH_16U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_S_MONO16:  cvImage = cvCreateImageHeader(mySize, 16, 1 );
                                     cvImage->depth = IPL_DEPTH_16U;
                                     cvImage->nChannels = 1;
                                     bColor = false;
                                     break;
        case PIXEL_FORMAT_S_RGB16:   cvImage = cvCreateImageHeader(mySize, 16, 3 );
                                     cvImage->depth = IPL_DEPTH_16U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_RAW8:      cvImage = cvCreateImageHeader(mySize, 8, 3 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_RAW16:     cvImage = cvCreateImageHeader(mySize, 8, 3 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_MONO12:    printf("Not supported by OpenCV");
                                     bColor = false;
                                     break;
        case PIXEL_FORMAT_RAW12:     printf("Not supported by OpenCV");
                                     break;
        case PIXEL_FORMAT_BGR:       cvImage = cvCreateImageHeader(mySize, 8, 3 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 3;
                                     break;
        case PIXEL_FORMAT_BGRU:      cvImage = cvCreateImageHeader(mySize, 8, 4 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 4;
                                     break;
        case PIXEL_FORMAT_RGBU:      cvImage = cvCreateImageHeader(mySize, 8, 4 );
                                     cvImage->depth = IPL_DEPTH_8U;
                                     cvImage->nChannels = 4;
                                     break;
        default: printf("Some error occured...\n");
                 return NULL;
    }

    if(bColor) {
        if(!bInitialized)
        {
            colorImage.SetData(new unsigned char[pImage->GetCols() * pImage->GetRows()*3], pImage->GetCols() * pImage->GetRows()*3);
            bInitialized = true;
        }

        pImage->Convert(PIXEL_FORMAT_BGR, &colorImage); //needs to be as BGR to be saved

        cvImage->width = colorImage.GetCols();
        cvImage->height = colorImage.GetRows();
        cvImage->widthStep = colorImage.GetStride();

        cvImage->origin = 0; //interleaved color channels

        cvImage->imageDataOrigin = (char*)colorImage.GetData(); //DataOrigin and Data same pointer, no ROI
        cvImage->imageData         = (char*)(colorImage.GetData());
        cvImage->widthStep      = colorImage.GetStride();
        cvImage->nSize = sizeof (IplImage);
        cvImage->imageSize = cvImage->height * cvImage->widthStep;
    }
    else
    {
        cvImage->imageDataOrigin = (char*)(pImage->GetData());
        cvImage->imageData         = (char*)(pImage->GetData());
        cvImage->widthStep         = pImage->GetStride();
        cvImage->nSize             = sizeof (IplImage);
        cvImage->imageSize         = cvImage->height * cvImage->widthStep;

        //at this point cvImage contains a valid IplImage
     }
    return cvImage;
}

在此处输入图像描述

4

1 回答 1

2

由于显而易见的原因，我无法测试下面的代码，但它说明了一种方法：

for ( int j = 0; j < k_numImages; j++ )
{
    // Display the timestamps for all cameras to show that the image
    // capture is synchronized for each image

    IplImage* destImage[3]; // A-ha moment

    for ( unsigned int i = 0; i < numCameras; i++ )
    {
        Image image;
        error = ppCameras[i]->RetrieveBuffer( &image );
        if (error != PGRERROR_OK)
        {
            PrintError( error );
            return -1;
        }

        /* Since ConvertImageToOpenCV() doesn't copy the image data,
         * we need to do that ourselves, because when this loop is done Image 
         * is destroyed and the data is lost.
         */
        IplImage* tmp = ConvertImageToOpenCV(&image);
        destImage[i] = cvCreateImage(cvGetSize(tmp), tmp->depth, tmp->nChannels);
        cvCopy(tmp, destImage[i], NULL); 

        char titolo[50];
        sprintf(titolo, "titolo%d", i);
    }

    cvShowManyImages("all", 3, destImage[0], destImage[1], destImage[2]);
    waitKey(0);

    // when you finish using them, release the allocated resources to prevent memory leaks
    cvReleaseImage(&destImage[0]);
    cvReleaseImage(&destImage[1]);
    cvReleaseImage(&destImage[2]);                 
}

这个想法是创建一个数组IplImage*来存储相机检索到的图像，因此在循环之后您可以访问所有这 3 个图像并能够在单个窗口上显示它们。

编辑：

总结一下私人聊天，问题在于cvShowManyImages()拍摄彩色（3通道）图像，而他的相机正在返回灰度（单通道）图像。解决方案是简单地改变cvShowManyImages(), 从：

DispImage = cvCreateImage( cvSize(100 + size*w, 60 + size*h), 8, 3 );

到：

DispImage = cvCreateImage( cvSize(100 + size*w, 60 + size*h), 8, 1 );
于 2012-06-01T12:50:12.363 回答