c++ - 如何防止控制台窗口超出屏幕？

Question

如果控制台应用程序启动并且系统为它创建控制台窗口，但有时这个窗口是在这样的坐标中创建的，它的一些内容会滑出右屏幕边缘。然后用户必须使用鼠标来显示一切。

如何应对？哪些函数用于检测控制台窗口的右上角坐标？然后我将能够检查它是否在屏幕之外并将窗口移动到所需的距离。

什么功能用于移动窗口？或者也许有一种解决方案可以防止窗口移动到屏幕外？

Answer 1

这是一个完全多显示器感知和任务栏感知的实现，可以按照您的描述进行操作。

#include <Windows.h>

int main()
{
  ClampConsoleToScreen();
  return 0;
}

void ClampConsoleToScreen()
{
  HWND window = GetConsoleWindow();
  RECT windowRect;
  GetWindowRect(window, &windowRect);
  HMONITOR monitor = MonitorFromWindow(window, MONITOR_DEFAULTTOPRIMARY);
  MONITORINFO mi;
  memset(&mi, 0, sizeof(mi));
  mi.cbSize = sizeof(mi);
  GetMonitorInfo(monitor, &mi);

  int adj, any;

  adj = 0;
  any = 0;
  if (windowRect.right > mi.rcWork.right)
  {
    // Get negative adjustment value to move it left onto screen
    adj = mi.rcWork.right - windowRect.right;
  }
  if (windowRect.left < mi.rcWork.left)
  {
    // Get positive adjustment value to move it right onto screen
    adj = mi.rcWork.left - windowRect.left;
  }
  windowRect.left += adj;
  windowRect.right += adj;
  any |= adj;

  adj = 0;
  if (windowRect.bottom > mi.rcWork.bottom)
  {
    // Get negative adjustment value to move it up onto screen
    adj = mi.rcWork.bottom - windowRect.bottom;
  }
  if (windowRect.top < mi.rcWork.top)
  {
    // Get positive adjustment value to move it down onto screen
    adj = mi.rcWork.top - windowRect.top;
  }
  windowRect.top += adj;
  windowRect.bottom += adj;
  any |= adj;

  if (any)
  {
    MoveWindow(window,
      windowRect.left,
      windowRect.top,
      windowRect.right - windowRect.left,
      windowRect.bottom - windowRect.top, TRUE);
  }
}