JVM 新手,使用 Scala 和 Play 2.0
我正在将一个遗留应用程序转换为 Play,它需要通过 Authorize.net 进行支付处理。查看 java.net.URL 源代码,有许多潜在的故障点。鉴于我在下面编写的接口,您将在哪里实现 try/catch 块?我需要相应地调整方法签名,可能会返回一个 Either[Error, Success] 来调用客户端代码
import java.net.{URL, URLEncoder}
import java.io.{BufferedReader, DataOutputStream, InputStreamReader}
import javax.net.ssl._
trait Authnet {
private val prodUrl = "https://secure.authorize.net/gateway/transact.dll"
private val testUrl = "https://test.authorize.net/gateway/transact.dll"
protected def authNetProcess(params: Map[String,String]) = {
val(conn, urlParams) = connect(params)
val request = new DataOutputStream( conn.getOutputStream )
request.write(urlParams.getBytes)
request.flush()
request.close()
val response = new BufferedReader(new InputStreamReader(conn.getInputStream))
val results = response.readLine().split("\\|")
response.close()
results.toList
}
private def connect(params: Map[String,String]) = {
val urlParams = (config ++ params) map { case(k,v) =>
URLEncoder.encode(k, "UTF-8") + "=" + URLEncoder.encode(v, "UTF-8")
} mkString("&")
lazy val url = if (isDev) new URL(testUrl) else new URL(prodUrl)
val conn = url.openConnection
conn.setDoOutput(true)
conn.setUseCaches(false)
(conn, urlParams)
}
private val config = Map(
'x_login -> "...",
'x_tran_key -> "...",
...
)
}