我对 Android 开发人员仍然很陌生并且被卡住了。我有一个 onTouchEvent，它为旋转图形提供动力并增加了一个背景 int [计数器]，它触发了一个短的声音效果（哔声）来播放。目前，如果 [counter] > 10 a 播放声音（使用 soundpool）并且只要 onTouchEvent 保持 counter > 10 就会立即循环播放。是否可以在哔声效果的播放之间插入延迟，以便延迟[counter] 的值越大越减小？
示例： if (counter == 10) { delay = 80 // 在 MS } if (counter == 90) { delay = 10 // 在 MS }
我的代码：
sm = new SoundManager();
sm.initSounds(getBaseContext());
sm.addSound(1, R.raw.beep);
...
@Override
public boolean onTouchEvent(MotionEvent event) {
if (buttonClicked) {
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
counter++;
startRotating();
break;
case MotionEvent.ACTION_UP:
counter--;
stopRotating();
break;
}
}
return super.onTouchEvent(event);
}
public void startRotating() {
returnRotating = false;
if (!keepRotating) {
keepRotating = true;
final Handler handler = new Handler();
handler.postDelayed(new Runnable() {
@Override
public void run() {
if (keepRotating) {
degrees = (degrees + 10) % 360;
make(degrees);
counter = counter + 1;
if (counter > 10)
sm.playSound(1); // plays beep
handler.postDelayed(this, INTERVAL);
}
}
}, INTERVAL);
}
}
编辑：添加代码
public void stopRotating() {
keepRotating = false;
if (!returnRotating) {
returnRotating = true;
final Handler handler = new Handler();
handler.postDelayed(new Runnable() {
@Override
public void run() {
if (returnRotating) {
degrees = (degrees - 10) % 360;
make(degrees);
counter = counter - 1;
if (counter > 10) {
sm.playSound(1); // plays beep
handler.postDelayed(this, INTERVAL);
}
}
}, INTERVAL);
}
}