7

我有这样的代码：

@dns = "#{params[:domain].split('/').reverse.join('.')}.#{params[:zone]}"
w = Whois::Client.new
@r = w.query(@dns)

有一条路线：

match "domains/:zone/*domain" => "domains#show"

我正在使用Whois Gem

我要测试的是，所以我有一个测试：

it "should query 'google.com.ua' from /ua/com/google" do
    get :show, :zone => 'ua', :domain => 'com/google'
    dns = "google.com.ua"
    Whois::Client.any_instance.should_receive(:query).with(dns)
end

结果我得到：

Exactly one instance should have received the following message(s) but didn't: query

问题可能出在哪里？我100%确定.query这叫

4

1 回答 1

13

看起来您可能在调用查询方法之后设置期望？

于 2012-05-31T16:25:57.453 回答